Toán a,25^3: 5^2 b,(3/7)^21: (9/49)^6 c, 3-(-6/7)^0 +(1/2)^2 :2 13/07/2021 By Valentina a,25^3: 5^2 b,(3/7)^21: (9/49)^6 c, 3-(-6/7)^0 +(1/2)^2 :2
`\text{a)}` `25^3 : 5^2` `= (5^2)^3 : 5^2` `= 5^6 : 5^2` `= 5^4` `\text{b)}` `(3/7)^21 : (9/49)^6` `= (3/7)^21 : [(3/7)^2]^6` `= (3/7)^21 : (3/7)^12` `= (3/7)^9` `\text{c)}` `3 – (-6/7)^0 + (1/2)^2 :2` `= 3 – 1 + 1/4 :2` `= 2 + 1/8` `=17/8` Trả lời
Đáp án: `a,` `25^3 ÷ 5^2` `= (5^2)^3 ÷ 5^2` `= 5^6 ÷ 5^2` `= 5^4` $\\$ `b,` `(3/7)^{21} ÷ (9/49)^6` `= (3/7)^{21} ÷ [(3/7)^2]^6` `= (3/7)^{21} ÷ (3/7)^{12}` `= (3/7)^{9}` $\\$ `c,` `3 – (-6/7)^0 + (1/2)^2 ÷ 2` `3 – 1 + 1/4 × 1/2` `= 3 – 1 + 1/8` `= 2 + 1/8` `= 16/8 + 1/8` `= 17/8` Trả lời
`\text{a)}`
`25^3 : 5^2`
`= (5^2)^3 : 5^2`
`= 5^6 : 5^2`
`= 5^4`
`\text{b)}`
`(3/7)^21 : (9/49)^6`
`= (3/7)^21 : [(3/7)^2]^6`
`= (3/7)^21 : (3/7)^12`
`= (3/7)^9`
`\text{c)}`
`3 – (-6/7)^0 + (1/2)^2 :2`
`= 3 – 1 + 1/4 :2`
`= 2 + 1/8`
`=17/8`
Đáp án:
`a,`
`25^3 ÷ 5^2`
`= (5^2)^3 ÷ 5^2`
`= 5^6 ÷ 5^2`
`= 5^4`
$\\$
`b,`
`(3/7)^{21} ÷ (9/49)^6`
`= (3/7)^{21} ÷ [(3/7)^2]^6`
`= (3/7)^{21} ÷ (3/7)^{12}`
`= (3/7)^{9}`
$\\$
`c,`
`3 – (-6/7)^0 + (1/2)^2 ÷ 2`
`3 – 1 + 1/4 × 1/2`
`= 3 – 1 + 1/8`
`= 2 + 1/8`
`= 16/8 + 1/8`
`= 17/8`