A, 273-[-34+27+273] B, 3^9:3^7-84:4+5^0 C, 27.(15-19)-19.(15-27) D, 58.75+58.50+25.(-58) 16/07/2021 Bởi Everleigh A, 273-[-34+27+273] B, 3^9:3^7-84:4+5^0 C, 27.(15-19)-19.(15-27) D, 58.75+58.50+25.(-58)
a, 273-[-34+27+273] =273+34-27-273 =(273-273)+(34-27) =0+7 =7 b, $3^9:3^7-84:4+5^0$ $=3^2-21+1$ $=9-21+1$ $=-11$ c, 27.(15-19)-19.(15-27) =27.15-27.19-19.15+19.27 =19.(-27+27)+15.(27-19) =10.0+15.8 =0+120 =120 d, 58.75+58.50+25.(-58) =58.(75-25)+58.50 =58.50+58.50 =2900×2 =5800 Bình luận
Đáp án: Giải thích các bước giải: a. 273 – ( -34 + 27 + 273 )= 273 + 34 – 27 – 273= ( 273 – 273 ) + ( 34 – 27 )= 0 + 7= 7 b. $3^{9}$ : $3^{7}$ – 84 : 4 + $5^{0}$ = $3^{2}$ – 21 + 1 = 9 – 21 + 1 = -11 c. 27 . ( 15 – 19 ) – 19.( 15 – 27 )= 27.15 – 27.19 – ( 19.15 – 19.27 )= 27.15 – 27.19 – 19.15 + 19.27= ( -27.19 + 19.27 ) + ( 27.15 – 19.15 )= 0 + 15.( 27 – 19 )= 15.8= 120 d. 58.75 + 58.50 + 25.(-58)= -58.(- 75 – 50 + 25 )= -58.( – 100 )= 5800 Bình luận
a, 273-[-34+27+273]
=273+34-27-273
=(273-273)+(34-27)
=0+7
=7
b, $3^9:3^7-84:4+5^0$
$=3^2-21+1$
$=9-21+1$
$=-11$
c, 27.(15-19)-19.(15-27)
=27.15-27.19-19.15+19.27
=19.(-27+27)+15.(27-19)
=10.0+15.8
=0+120
=120
d, 58.75+58.50+25.(-58)
=58.(75-25)+58.50
=58.50+58.50
=2900×2
=5800
Đáp án:
Giải thích các bước giải:
a. 273 – ( -34 + 27 + 273 )
= 273 + 34 – 27 – 273
= ( 273 – 273 ) + ( 34 – 27 )
= 0 + 7
= 7
b. $3^{9}$ : $3^{7}$ – 84 : 4 + $5^{0}$
= $3^{2}$ – 21 + 1
= 9 – 21 + 1
= -11
c. 27 . ( 15 – 19 ) – 19.( 15 – 27 )
= 27.15 – 27.19 – ( 19.15 – 19.27 )
= 27.15 – 27.19 – 19.15 + 19.27
= ( -27.19 + 19.27 ) + ( 27.15 – 19.15 )
= 0 + 15.( 27 – 19 )
= 15.8
= 120
d. 58.75 + 58.50 + 25.(-58)
= -58.(- 75 – 50 + 25 )
= -58.( – 100 )
= 5800