a, ( 3x – 1 ) (-1/2 x + 5 ) = 0 b, -2/3 – 1/3 ( 2x – 5 ) = 3/2 c, x-12/4 = 1/2 Giúp mình vs

0 bình luận về “a, ( 3x – 1 ) (-1/2 x + 5 ) = 0 b, -2/3 – 1/3 ( 2x – 5 ) = 3/2 c, x-12/4 = 1/2 Giúp mình vs”

1. Đáp án: + Giải thích các bước giải:

   `a//`

    `(3x – 1)(-1/(2x+5)) = 0`

   `\to 3x – 1= 0`

   `\to 3x = 1`

   `\to x = 1/3`

   Vậy `x = 1/3`

   `b//`

   `-2/3 – 1/3 ( 2x – 5 ) = 3/2`

   `\to -1/3 (2x – 5) = 13/6`

   `\to 2x – 5 = -13/2`

   `\to 2x = -3/2`

   `\to x = – 3/4`

   Vậy `x = -3/4`

   `c//`

   `x – 12/4 = 1/2`

   `\to x = 1/2 + 12/4`

   `\to x = 14/4`

   Vậy `x = 14/4`

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2. `a,`

   `( 3x – 1 ) (-1/2 x + 5 ) = 0`

   `⇒3x-1=0`

   `⇒3x=1`

   `⇒x=1/3`

   `hoặc`

   `(-1/2 x + 5 ) = 0`

   `⇒-1/2x=-5`

   `⇒x=10`

   `b,`

   `-2/3 – 1/3 ( 2x – 5 ) = 3/2`

   `⇒ – 1/3 ( 2x – 5 ) = -2/3 – 3/2`

   `⇒ – 1/3 ( 2x – 5 ) = -13/6`

   `⇒2x – 5 = -13/6 : -1/3`

   `⇒2x-5=13/2`

   `⇒2x=13/2 +5`

   `⇒2x=23/2`

   `⇒x=23/4`

   `c,`

   `x-12/4 = 1/2`

   `⇒x=1/2 + 12/4`

   `⇒x=7/2`

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