a . 3.15 – 4^2 . 1^2019 + 5^2 b. ( 2^78 + 2^79+ 2^80) : ( 2^75+2^76+2^77) c. ( 12x – 140) . 5^14 = 4. 5^10 08/07/2021 Bởi Iris a . 3.15 – 4^2 . 1^2019 + 5^2 b. ( 2^78 + 2^79+ 2^80) : ( 2^75+2^76+2^77) c. ( 12x – 140) . 5^14 = 4. 5^10
Đáp án: Giải thích các bước giải: a . `3.15 – 4^2 . 1^2019 + 5^2` `=45-16.1+25` `=29+25` `=54` b. `( 2^78 + 2^79+ 2^80) : ( 2^75+2^76+2^77)` `= (2^78 + 2^78. 2^1 + 2^78. 2^2) : (2^75 + 2^75 . 2^1 + 2^75. 2^2)` `= [2^78. (1 + 2^1 + 2^2)] : [2^75. (1 + 2^1 + 2^2)]` `= 2^78 : 2^75` `= 2^3` `= 8` c. `( 12x – 140) . 5^14 = 4. 5^10` Bình luận
a. 3 . 15 – $4^{2}$ . $1^{2019}$ + $5^{2}$ = 45 – 16 . 1 + 25 = 45 – 16 + 25 = 29 + 25 = 54 b. ( $2^{78}$ + $2^{79}$ + $2^{80}$ ) ÷ ( $2^{75}$ + $2^{76}$ + $2^{77}$ ) = ( $2^{78}$ + $2^{78}$ . 2 + $2^{78}$ . $2^{2}$ ) + ( $2^{75}$ + $2^{75}$ . 2 + $2^{75}$ . $2^{2}$ ) = [ $2^{78}$ . ( 1 + 2 + $2^{2}$ ] + [ $2^{75}$ . ( 1 + 2 + $2^{2}$ ) ] = $2^{78}$ ÷ $2^{75}$ = $2^{3}$ = 8 Ý c số to quá b ạ Bình luận
Đáp án:
Giải thích các bước giải:
a . `3.15 – 4^2 . 1^2019 + 5^2`
`=45-16.1+25`
`=29+25`
`=54`
b. `( 2^78 + 2^79+ 2^80) : ( 2^75+2^76+2^77)`
`= (2^78 + 2^78. 2^1 + 2^78. 2^2) : (2^75 + 2^75 . 2^1 + 2^75. 2^2)`
`= [2^78. (1 + 2^1 + 2^2)] : [2^75. (1 + 2^1 + 2^2)]`
`= 2^78 : 2^75`
`= 2^3`
`= 8`
c. `( 12x – 140) . 5^14 = 4. 5^10`
a. 3 . 15 – $4^{2}$ . $1^{2019}$ + $5^{2}$
= 45 – 16 . 1 + 25
= 45 – 16 + 25
= 29 + 25
= 54
b. ( $2^{78}$ + $2^{79}$ + $2^{80}$ ) ÷ ( $2^{75}$ + $2^{76}$ + $2^{77}$ )
= ( $2^{78}$ + $2^{78}$ . 2 + $2^{78}$ . $2^{2}$ ) + ( $2^{75}$ + $2^{75}$ . 2 + $2^{75}$ . $2^{2}$ )
= [ $2^{78}$ . ( 1 + 2 + $2^{2}$ ] + [ $2^{75}$ . ( 1 + 2 + $2^{2}$ ) ]
= $2^{78}$ ÷ $2^{75}$
= $2^{3}$
= 8
Ý c số to quá b ạ