a) | x + 3/4| – 1/3 = 0 b) | x + 13/7| + | x + 2020/2021| + | x – 1| = 0 07/08/2021 Bởi Audrey a) | x + 3/4| – 1/3 = 0 b) | x + 13/7| + | x + 2020/2021| + | x – 1| = 0
a) | x + $\frac{3}{4}$ | – $\frac{1}{3}$ = 0 | x + $\frac{3}{4}$ | = 0 + $\frac{1}{3}$ | x + $\frac{3}{4}$ | = $\frac{1}{3}$ TH1 : x + $\frac{3}{4}$ = $\frac{1}{3}$ x= $\frac{1}{3}$ – $\frac{3}{4}$ x= $\frac{-5}{12}$ TH2: x + $\frac{3}{4}$ = – $\frac{1}{3}$ x= -$\frac{1}{3}$ – $\frac{3}{4}$ x=- $\frac{13}{12}$ b) | x + 13/7| + | x + 2020/2021| + | x – 1| = 0 x + 13/7 = 0 x= – 13/7 x + 2020/2021 = 0 x= – 2020/2021 x – 1 = 0 x= 1 Bình luận
a) l x + 3/4 l -1/3 =0 l x + 3/4 l = 0 + 1/3 x+ 3/4 = 1/3 hoặc x + 3/4 = -1/3 x=1/3 – 3/4 x = -1/3 – 3/4 x = 4/12 – 9/12 x= -4/12 – 9/12 x = -5/12 x = -13/12 vậy x = { -5/12 ; -13/12 } Chúc bạn học tốt nhé nếu hay cho 5* nha Bình luận
a) | x + $\frac{3}{4}$ | – $\frac{1}{3}$ = 0
| x + $\frac{3}{4}$ | = 0 + $\frac{1}{3}$
| x + $\frac{3}{4}$ | = $\frac{1}{3}$
TH1 :
x + $\frac{3}{4}$ = $\frac{1}{3}$
x= $\frac{1}{3}$ – $\frac{3}{4}$
x= $\frac{-5}{12}$
TH2:
x + $\frac{3}{4}$ = – $\frac{1}{3}$
x= -$\frac{1}{3}$ – $\frac{3}{4}$
x=- $\frac{13}{12}$
b) | x + 13/7| + | x + 2020/2021| + | x – 1| = 0
x + 13/7 = 0
x= – 13/7
x + 2020/2021 = 0
x= – 2020/2021
x – 1 = 0
x= 1
a) l x + 3/4 l -1/3 =0
l x + 3/4 l = 0 + 1/3
x+ 3/4 = 1/3 hoặc x + 3/4 = -1/3
x=1/3 – 3/4 x = -1/3 – 3/4
x = 4/12 – 9/12 x= -4/12 – 9/12
x = -5/12 x = -13/12
vậy x = { -5/12 ; -13/12 }
Chúc bạn học tốt nhé
nếu hay cho 5* nha