a) 3(x + 7 ) +9 = 9 – 2 ( x + 5 ) b) 218 – ( x + 31 = x – 29

a) 3(x + 7 ) +9 = 9 – 2 ( x + 5 )
b) 218 – ( x + 31 = x – 29

0 bình luận về “a) 3(x + 7 ) +9 = 9 – 2 ( x + 5 ) b) 218 – ( x + 31 = x – 29”

  1. `\text{~~Holi~~}`

    `a. 3(x+7)+9=9-2(x+5)`

    `-> 3x+21+9=9-2x-10`

    `-> 3x+21+9-9+2x+10=0`

    `-> 5x+31=0`

    `-> 5x=-31`

    `-> x=-31/5`

    Vậy `x=-31/5`

    `b. 218-(x+31)=x-29`

    `-> 218-x-31=x-29`

    `-> 218-x-31-x+29=0`

    `-> 216-2x=0`

    `-> 2x=216`

    `-> x=216/2`

    `-> x=108`

    Vậy `x=108`

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  2. `a) 3(x + 7 ) +9 = 9 – 2 ( x + 5 )`

    `⇔3x+21+9=9-2x-10`

    `⇔3x+2x=9-9-10-21`

    `⇔5x=-31`

    `⇔x=-{31}/5`

    `b) 218 – ( x + 31) = x – 29`

    `⇔218-x-31=x-29`

    `⇔-x-x=-29+31-218`

    `⇔-2x=-216`

    `⇔x={-216}/{-2}`

    `⇔x=108`

     

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