Đáp án: Giải thích các bước giải: a) 3x- l2-5xl =4 ⇔ l2-5xl = 4 – 3x ⇔\(\left[ \begin{array}{l}2-5x=4-3x\\2-5x=-4+3x\end{array} \right.\) ⇔\(\left[ \begin{array}{l}-2x=2\\8x=6\end{array} \right.\) ⇔\(\left[ \begin{array}{l}x=-1\\x=\frac{6}{8} \end{array} \right.\) b) l2x+3l-3x=1 ⇔ l2x+3l=1+3x ⇔\(\left[ \begin{array}{l}2x+3=1+3x\\2x+3=-1-3x\end{array} \right.\) ⇔\(\left[ \begin{array}{l}-x=-2\\5x=2\end{array} \right.\) ⇔\(\left[ \begin{array}{l}x=2\\x=\frac{2}{5}\end{array} \right.\) Bình luận
Đáp án:
Giải thích các bước giải:
a) 3x- l2-5xl =4
⇔ l2-5xl = 4 – 3x
⇔\(\left[ \begin{array}{l}2-5x=4-3x\\2-5x=-4+3x\end{array} \right.\)
⇔\(\left[ \begin{array}{l}-2x=2\\8x=6\end{array} \right.\)
⇔\(\left[ \begin{array}{l}x=-1\\x=\frac{6}{8} \end{array} \right.\)
b) l2x+3l-3x=1
⇔ l2x+3l=1+3x
⇔\(\left[ \begin{array}{l}2x+3=1+3x\\2x+3=-1-3x\end{array} \right.\)
⇔\(\left[ \begin{array}{l}-x=-2\\5x=2\end{array} \right.\)
⇔\(\left[ \begin{array}{l}x=2\\x=\frac{2}{5}\end{array} \right.\)