A=3 mũ 2010-(3 mũ 2009+3 mũ 2008+3 mũ 2007+…..+3 mũ 2+3+1) 05/12/2021 Bởi Valerie A=3 mũ 2010-(3 mũ 2009+3 mũ 2008+3 mũ 2007+…..+3 mũ 2+3+1)
Đáp án : `A=(3^(2010)+1)/2` Giải thích các bước giải : `A=3^(2010)-(3^(2009)+3^(2008)+3^(2007)+…+3^2+3+1)` `+)Đặt B=3^(2009)+3^(2008)+3^(2007)+…+3^2+3+1` `<=>3B=3^(2010)+3^(2009)+3^(2008)+…+3^3+3^2+3` `<=>3B-B=(3^(2010)+3^(2009)+…+3^2+3)-(3^(2009)+3^(2008)+…+3+1)` `<=>2B=3^(2010)-1` `<=>B=(3^(2010)-1)/2` `<=>A=3^(2010)-(3^(2010)-1)/2` `<=>A=[2.3^(2010)]/2-(3^(2010)-1)/2` `<=>A=(2.3^(2010)-3^(2010)+1)/2` `<=>A=(3^(2010)+1)/2` Vậy `A=(3^(2010)+1)/2` ~Chúc bạn hoc tốt !!!~ Bình luận
Đáp án :
`A=(3^(2010)+1)/2`
Giải thích các bước giải :
`A=3^(2010)-(3^(2009)+3^(2008)+3^(2007)+…+3^2+3+1)`
`+)Đặt B=3^(2009)+3^(2008)+3^(2007)+…+3^2+3+1`
`<=>3B=3^(2010)+3^(2009)+3^(2008)+…+3^3+3^2+3`
`<=>3B-B=(3^(2010)+3^(2009)+…+3^2+3)-(3^(2009)+3^(2008)+…+3+1)`
`<=>2B=3^(2010)-1`
`<=>B=(3^(2010)-1)/2`
`<=>A=3^(2010)-(3^(2010)-1)/2`
`<=>A=[2.3^(2010)]/2-(3^(2010)-1)/2`
`<=>A=(2.3^(2010)-3^(2010)+1)/2`
`<=>A=(3^(2010)+1)/2`
Vậy `A=(3^(2010)+1)/2`
~Chúc bạn hoc tốt !!!~