a) 3 ⁞ ( n + 1) b) 10 ⁞ ( 2n + 5) b) c) -11 ⁞ ( n – 1) d) ( n – 5)2 – 2.(n – 5) + 7 ⁞ (n – 5) 01/12/2021 Bởi Rose a) 3 ⁞ ( n + 1) b) 10 ⁞ ( 2n + 5) b) c) -11 ⁞ ( n – 1) d) ( n – 5)2 – 2.(n – 5) + 7 ⁞ (n – 5)
Đáp án: Giải thích các bước giải: $3$ $\vdots$ $n+1$ $⇒n+1∈${$3;1;-1;-3$} $⇒n∈${$2;0;-2;-4$} $ $ $10$ $\vdots$ $2n+5$ $⇒2n+5∈${$10;5;2;1;-1;-2;-5;-10$} $⇒2n∈${$5;0;-3;-4;-6;-7;-10;-15$} $⇒n∈${$\dfrac{5}{2};0;\dfrac{-3}{2};-2;-3;\dfrac{-7}{2};-5;\dfrac{-15}{2}$} $ $ $-11$ $\vdots$ $n-1$ $⇒n-1∈${$11;1;-1;-11$} $⇒n∈${$12;2;0;-10$} $ $ $(n-5)^{2}-2.(n-5)+7$ $\vdots$ $n-5$ $⇒(n-5).(n-5-2)+7$ $\vdots$ $n-5$ $⇒7$ $\vdots$ $n-5$ $⇒n-5∈${$7;1;-1;-7$} $⇒n∈${$12;6;4;-2$} Bình luận
Đáp án:
Giải thích các bước giải:
$3$ $\vdots$ $n+1$
$⇒n+1∈${$3;1;-1;-3$}
$⇒n∈${$2;0;-2;-4$}
$ $
$10$ $\vdots$ $2n+5$
$⇒2n+5∈${$10;5;2;1;-1;-2;-5;-10$}
$⇒2n∈${$5;0;-3;-4;-6;-7;-10;-15$}
$⇒n∈${$\dfrac{5}{2};0;\dfrac{-3}{2};-2;-3;\dfrac{-7}{2};-5;\dfrac{-15}{2}$}
$ $
$-11$ $\vdots$ $n-1$
$⇒n-1∈${$11;1;-1;-11$}
$⇒n∈${$12;2;0;-10$}
$ $
$(n-5)^{2}-2.(n-5)+7$ $\vdots$ $n-5$
$⇒(n-5).(n-5-2)+7$ $\vdots$ $n-5$
$⇒7$ $\vdots$ $n-5$
$⇒n-5∈${$7;1;-1;-7$}
$⇒n∈${$12;6;4;-2$}