a) (x-32).45=90 b) 3^2x+1=81 c)(x-1/3)^2-1/4=0

a) (x-32).45=90 b) 3^2x+1=81 c)(x-1/3)^2-1/4=0

0 bình luận về “a) (x-32).45=90 b) 3^2x+1=81 c)(x-1/3)^2-1/4=0”

  1. a) (x-32).45=90

    x-32=90:45

    x-32=2

    x=2+32

    x=34

    b)3^2x+1=81

    3^2x=81-1

    9x=80

    x=80:9

    => x ∈∅

    c)(x-1/3)^2-1/4=0

    (x-1/3)^2=0+1/4

    (x-1/3)^2=1/4

    (x-1/3)^2=(±1/2)^2

    => x-1/3=±1/2

    TH1:

    x-1/3=1/2

    x=1/2+1/3

    x=3/6+2/6

    x=5/6

    TH2:

    x-1/3=-1/2

    x=-1/2+1/3

    x=-3/6+2/6

    x=-1/6

    #chucbanhoctot

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  2. a) `(x-32).45 = 90`

    `x-32=90:45`

    `x-32=2`

    `x=2+32`

    `x=34`

    b) `3^(2x + 1)=81`

     `3^(2x+1) = 3^4`

    `2x+1=4`

    `2x=3`

    `x=3/2`

    c) `(x-1/3)^2 -1/4 =0`

    `(x-1/3)^2 = 1/4`

    `(x-1/3) = \pm 1/2`

    `x = 5/6` hoặc `x=-1/6`

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