a) (x-32).45=90 b) 3^2x+1=81 c)(x-1/3)^2-1/4=0 06/11/2021 Bởi Arya a) (x-32).45=90 b) 3^2x+1=81 c)(x-1/3)^2-1/4=0
a) (x-32).45=90 x-32=90:45 x-32=2 x=2+32 x=34 b)3^2x+1=81 3^2x=81-1 9x=80 x=80:9 => x ∈∅ c)(x-1/3)^2-1/4=0 (x-1/3)^2=0+1/4 (x-1/3)^2=1/4 (x-1/3)^2=(±1/2)^2 => x-1/3=±1/2 TH1: x-1/3=1/2 x=1/2+1/3 x=3/6+2/6 x=5/6 TH2: x-1/3=-1/2 x=-1/2+1/3 x=-3/6+2/6 x=-1/6 #chucbanhoctot Bình luận
a) `(x-32).45 = 90` `x-32=90:45` `x-32=2` `x=2+32` `x=34` b) `3^(2x + 1)=81` `3^(2x+1) = 3^4` `2x+1=4` `2x=3` `x=3/2` c) `(x-1/3)^2 -1/4 =0` `(x-1/3)^2 = 1/4` `(x-1/3) = \pm 1/2` `x = 5/6` hoặc `x=-1/6` Bình luận
a) (x-32).45=90
x-32=90:45
x-32=2
x=2+32
x=34
b)3^2x+1=81
3^2x=81-1
9x=80
x=80:9
=> x ∈∅
c)(x-1/3)^2-1/4=0
(x-1/3)^2=0+1/4
(x-1/3)^2=1/4
(x-1/3)^2=(±1/2)^2
=> x-1/3=±1/2
TH1:
x-1/3=1/2
x=1/2+1/3
x=3/6+2/6
x=5/6
TH2:
x-1/3=-1/2
x=-1/2+1/3
x=-3/6+2/6
x=-1/6
#chucbanhoctot
a) `(x-32).45 = 90`
`x-32=90:45`
`x-32=2`
`x=2+32`
`x=34`
b) `3^(2x + 1)=81`
`3^(2x+1) = 3^4`
`2x+1=4`
`2x=3`
`x=3/2`
c) `(x-1/3)^2 -1/4 =0`
`(x-1/3)^2 = 1/4`
`(x-1/3) = \pm 1/2`
`x = 5/6` hoặc `x=-1/6`