a)x^4+2x^3-2x^2-1 b)x^2+2x-4y^2-4y c)a^2(b-c)+b^2(c-a)+c^2(a-b) d)(x-y)^3+(x-z)^3+(z-x)^3 18/08/2021 Bởi Charlie a)x^4+2x^3-2x^2-1 b)x^2+2x-4y^2-4y c)a^2(b-c)+b^2(c-a)+c^2(a-b) d)(x-y)^3+(x-z)^3+(z-x)^3
a)x^4+2x³-2x²-1 =(x²)²-1+2x³-2x² =(x²-1)(x²+1)+2x³-2x² =(x-1)(x+1)(x²+1)+2x²(x-1) =(x-1)[(x+1)(x²+1)+2x²] =(x-1)[x³+x+x²+1+2x²] =(x-1)[x³+3x²+x+1] =(x-1)(x³+3x²+x+1) b)x²+2x-4y²-4y =x²+2x+1-(2y)²-2.y.2-1 =(x²+2x+1)-[(2y)²+2.y.2+1] =(x+1)²-(2y+1)² =[(x+1)-(2y+1)][(x+1)+(2y+1)] =(x+1-2y-1)(x+1+2y+1) =(x-2y)(x+2y+2) c)a²(b-c)+b²(c-a)+c²(a-b) =a²b-a²c+b²c-ab²+ac²-bc² =a²b-ab²-a²c+b²c+ac²-bc² =ab(a-b)-c(a²-b²)+c²(a-b) =ab(a-b)-c(a-b)(a+b)+c²(a-b) =(a-b)[ab-c(a+b)+c²] =(a-b)(ab-ac-bc+c²) =(a-b)(ab-bc-ac+c²) =(a-b)[b(a-c)-c(a-c)] =(a-b)[(a-c)(b-c)] =(a-b)(a-c)(b-c) d)(x-y)³+(x-z)³+(z-x)³ =x³-3x²y+3xy²-y³+{(x-z+z-x)[(x-z)²-(x-z)(z-x)+(z-x)²} =x³-3x²y+3xy²-y³+(0.[(x-z)²-(x-z)(z-x)+(z-x)²] =x³-3x²y+3xy²-y³+0 =x³-3x²y+3xy²-y³ Chúc bạn học tốt!!! ^_^ ^_^ ^_^ Bình luận
a)x^4+2x³-2x²-1
=(x²)²-1+2x³-2x²
=(x²-1)(x²+1)+2x³-2x²
=(x-1)(x+1)(x²+1)+2x²(x-1)
=(x-1)[(x+1)(x²+1)+2x²]
=(x-1)[x³+x+x²+1+2x²]
=(x-1)[x³+3x²+x+1]
=(x-1)(x³+3x²+x+1)
b)x²+2x-4y²-4y
=x²+2x+1-(2y)²-2.y.2-1
=(x²+2x+1)-[(2y)²+2.y.2+1]
=(x+1)²-(2y+1)²
=[(x+1)-(2y+1)][(x+1)+(2y+1)]
=(x+1-2y-1)(x+1+2y+1)
=(x-2y)(x+2y+2)
c)a²(b-c)+b²(c-a)+c²(a-b)
=a²b-a²c+b²c-ab²+ac²-bc²
=a²b-ab²-a²c+b²c+ac²-bc²
=ab(a-b)-c(a²-b²)+c²(a-b)
=ab(a-b)-c(a-b)(a+b)+c²(a-b)
=(a-b)[ab-c(a+b)+c²]
=(a-b)(ab-ac-bc+c²)
=(a-b)(ab-bc-ac+c²)
=(a-b)[b(a-c)-c(a-c)]
=(a-b)[(a-c)(b-c)]
=(a-b)(a-c)(b-c)
d)(x-y)³+(x-z)³+(z-x)³
=x³-3x²y+3xy²-y³+{(x-z+z-x)[(x-z)²-(x-z)(z-x)+(z-x)²}
=x³-3x²y+3xy²-y³+(0.[(x-z)²-(x-z)(z-x)+(z-x)²]
=x³-3x²y+3xy²-y³+0
=x³-3x²y+3xy²-y³
Chúc bạn học tốt!!! ^_^ ^_^ ^_^
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