a][4-x][x-3]=0 b]2x-8][1-x]=0 c][15-3x][x-6]=0

0 bình luận về “a][4-x][x-3]=0 b]2x-8][1-x]=0 c][15-3x][x-6]=0”

1. a][4-x][x-3]=0

   => [4-x] = 0 hoặc [x-3] = 0

   => 4-x = 0 hoặc x – 3 = 0

   => x = 4 hoặc x = 3 (T/M)

   b][2x-8][1-x]=0

   => [2x-8]=0 hoặc [1-x]=0

   => 2x-8=0 hoặc 1-x = 0

   => 2x = 8 hoặc x = 1

   => x = 4 hoặc x=1 (T/M)

   c][15-3x][x-6]=0 

   => [15-3x]=0 hoặc [x-6]=0

   => 15-3x=0 hoặc x-6=0

   => 3x = 15 hoặc x = 6

   => x = 5 hoặc x = 6 (T/M)

   HỌC TỐT 😀

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2. ${a)(4-x)(x-3)=0}$
   ⇒\(\left[ \begin{array}{l}4-x=0\\x-3=0\end{array} \right.\) 
   ⇒\(\left[ \begin{array}{l}x=4\\x=3\end{array} \right.\)

   $\text{Vậy \(\left[ \begin{array}{l}x=4\\x=3\end{array} \right.\)}$

   ${b)(2x-8)(1-x)=0}$

   ⇒\(\left[ \begin{array}{l}2x-8=0\\1-x=0\end{array} \right.\) 
   ⇒\(\left[ \begin{array}{l}2x=8\\x=1-0\end{array} \right.\)

   ⇒ \(\left[ \begin{array}{l}x=4\\x=1\end{array} \right.\)

   $\text{Vậy \(\left[ \begin{array}{l}x=4\\x=1\end{array} \right.\)}$

   ${b)(15-3x)(x-6)=0}$

   ⇒\(\left[ \begin{array}{l}15-3x=0\\x-6=0\end{array} \right.\) 
   ⇒\(\left[ \begin{array}{l}3x=15\\x=0+6\end{array} \right.\)

   ⇒ \(\left[ \begin{array}{l}x=5\\x=6\end{array} \right.\)

   $\text{Vậy \(\left[ \begin{array}{l}x=5\\x=6\end{array} \right.\)}$

   $\text{STUDY WELL !}$

    

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