A=4 mũ 5*9 mũ 4-2*6 mũ 9 phần 2 mũ 10*3 mũ 8+6 mũ 8*20 18/07/2021 Bởi Clara A=4 mũ 5*9 mũ 4-2*6 mũ 9 phần 2 mũ 10*3 mũ 8+6 mũ 8*20
Đáp án: `A=-1/3` Giải thích các bước giải: `A=(4 ^ 5 . 9 ^ 4-2 . 6 ^ 9) / (2 ^ 10 . 3 ^8 + 6 ^ 8 . 20)``A=[(2^2) ^ 5 . (3^2) ^ 4-2 . (2.3) ^ 9] / (2 ^ 10 . 3 ^8 + 6 ^ 8 . 20)``A=[2^(2 . 5) . 3^(2.4)-2 . 2^9 . 3 ^ 9] / (2 ^ 10 . 3 ^8 + 6 ^ 8 . 20)``A=[2^10 . 3^8-2^(1+9) . 3 ^ 9] / (2 ^ 10 . 3 ^8 + (2.3) ^ 8 . 20)``A=[2^10 . 3^8-2^10 . 3 ^ 9] / (2 ^ 10 . 3 ^8 + 2 ^ 8 . 3^8 . 20)``A=[2^10 . (3^8 -3^9)] / (2 ^ 10 . 3 ^8 + 2 ^ 8 . 3^8 . 20)``A=[2^10 . (3^8 -3^9)] / (2 ^ 10 . 3 ^8 + 2 ^ 8 . 3^8 . 2.10)``A=[2^10 . (3^8 -3^9)] / (2 ^ 10 . 3 ^8 + 2 ^ 8 . 2. 3^8 . 10)``A=[2^10 . (3^8 -3^9)] / (2 ^ 10 . 3 ^8 + 2 ^ (8+1). 3^8 . 10)``A=[2^10 . (3^8 -3^9)] / (2 ^ 10 . 3 ^8 + 2 ^ 9. 3^8 . 2.5)``A=[2^10 . (3^8 -3^9)] / (2 ^ 10 . 3 ^8 + 2 ^ 9. 2. 3^8 .5)``A=[2^10 . (3^8 -3^9)] / (2 ^ 10 . 3 ^8 + 2 ^ (9+1). 3^8 .5)``A=[2^10 . (3^8 -3^9)] / (2 ^ 10 . 3 ^8 + 2 ^ 10. 3^8 .5)``A=[2^10 . (3^8 -3^9)] / [2 ^ 10 .(3^8 + 3^8. 5)``A=[3^8-3^9]/[3^8 + 3^8 .5]``A=[3^8 . 1-3^8 . 3]/[3^8.1 + 3^8 . 5]``A=[3^8 .(1-3)]/[3^8.(1+5)]``A=[3^8 .(-2)]/[3^8. 6]``A=-2/6``A=-1/3``text{Vậy }` `A=-1/3` Bình luận
Đáp án:
`A=-1/3`
Giải thích các bước giải:
`A=(4 ^ 5 . 9 ^ 4-2 . 6 ^ 9) / (2 ^ 10 . 3 ^8 + 6 ^ 8 . 20)`
`A=[(2^2) ^ 5 . (3^2) ^ 4-2 . (2.3) ^ 9] / (2 ^ 10 . 3 ^8 + 6 ^ 8 . 20)`
`A=[2^(2 . 5) . 3^(2.4)-2 . 2^9 . 3 ^ 9] / (2 ^ 10 . 3 ^8 + 6 ^ 8 . 20)`
`A=[2^10 . 3^8-2^(1+9) . 3 ^ 9] / (2 ^ 10 . 3 ^8 + (2.3) ^ 8 . 20)`
`A=[2^10 . 3^8-2^10 . 3 ^ 9] / (2 ^ 10 . 3 ^8 + 2 ^ 8 . 3^8 . 20)`
`A=[2^10 . (3^8 -3^9)] / (2 ^ 10 . 3 ^8 + 2 ^ 8 . 3^8 . 20)`
`A=[2^10 . (3^8 -3^9)] / (2 ^ 10 . 3 ^8 + 2 ^ 8 . 3^8 . 2.10)`
`A=[2^10 . (3^8 -3^9)] / (2 ^ 10 . 3 ^8 + 2 ^ 8 . 2. 3^8 . 10)`
`A=[2^10 . (3^8 -3^9)] / (2 ^ 10 . 3 ^8 + 2 ^ (8+1). 3^8 . 10)`
`A=[2^10 . (3^8 -3^9)] / (2 ^ 10 . 3 ^8 + 2 ^ 9. 3^8 . 2.5)`
`A=[2^10 . (3^8 -3^9)] / (2 ^ 10 . 3 ^8 + 2 ^ 9. 2. 3^8 .5)`
`A=[2^10 . (3^8 -3^9)] / (2 ^ 10 . 3 ^8 + 2 ^ (9+1). 3^8 .5)`
`A=[2^10 . (3^8 -3^9)] / (2 ^ 10 . 3 ^8 + 2 ^ 10. 3^8 .5)`
`A=[2^10 . (3^8 -3^9)] / [2 ^ 10 .(3^8 + 3^8. 5)`
`A=[3^8-3^9]/[3^8 + 3^8 .5]`
`A=[3^8 . 1-3^8 . 3]/[3^8.1 + 3^8 . 5]`
`A=[3^8 .(1-3)]/[3^8.(1+5)]`
`A=[3^8 .(-2)]/[3^8. 6]`
`A=-2/6`
`A=-1/3`
`text{Vậy }` `A=-1/3`