a, 457+(217-x)=589 b,96-3(x+1)=42 c,5.(x+35)=515 d,70-5(x-3)=45 e,10+2.x=4 mũ 5: 4 mũ 3

0 bình luận về “a, 457+(217-x)=589 b,96-3(x+1)=42 c,5.(x+35)=515 d,70-5(x-3)=45 e,10+2.x=4 mũ 5: 4 mũ 3”

1. $a$) $457 + (217 – x) = 589$

   $⇔ 217 – x = 132$

   $⇔ x = 85$

     Vậy $x=85$.

   $b$) $96 – 3(x+1)=42$

   $⇔ 3(x+1) = 54$

   $⇔ x+1 = 18$

   $⇔ x= 17$

     Vậy $x=17$.

   $c$) $5.(x+35)=515$

   $⇔ x+35 = 103$

   $⇔ x  = 68$

     Vậy $x=68$.

   $d$) $70 – 5(x-3) = 45$

   $⇔ 5(x-3) = 25$

   $⇔ x-3 = 5$

   $⇔ x = 8$

     Vậy $x=8$.

   $e$) $10 + 2x = 4^5 : 4^3$

   $⇔ 10+2x = 4^2$

   $⇔ 10+2x = 16$

   $⇔ 2x = 6$

   $⇔ x = 3$

     Vậy $x=3$.

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2. a) 217 – x = 132 <=> x= 217-132=85

   b) 3(x+1) = 54 <=> x+1 = 18 <=> x=17

   c) x+35 = 103 <=> x=68

   d) 5(x-3) = 25 <=> x-3=5 <=> x=8

   e) 10 + 2x = 1024 : 64 <=> 10 + 2x = 16 <=> 2x= 6 <=> x=3

    

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