a,|5-x|=12 b,(25+x)=250 c,15+(x-10)=23 d,11-(-53+x)=97 e,61+(x-23)=91

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1. a)`|5-x|=12`

   `⇔`\(\left[ \begin{array}{l}5-x=12\\5-x=-12\end{array} \right.\) 

   `⇔`\(\left[ \begin{array}{l}x=-7\\x=17\end{array} \right.\) 

   b)`25+x=250`

   `⇒x=225`

   c)`15+(x-10)=23`

   `⇒x-10=8`

   `⇒x=18`

   d)`11-(-53+x)=97`

   `⇒-53+x=-86`

   `⇒x=-86+53`

   `⇒x=-33`

   e)`61+(x-23)=91`

   `⇒x-23=30`

   `⇒x=53`

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2. a, |5-x|=12

   => \(\left[ \begin{array}{l}5-x=12\\5-x=-12\end{array} \right.\) 

   => \(\left[ \begin{array}{l}x= -7\\x=17\end{array} \right.\)

   Vậy \(\left[ \begin{array}{l}x= -7\\x=17\end{array} \right.\)

   ——————–

   b, 25+x=250

   => x= 250-25

   => x= 225

   Vậy x=225

   ————————–

   c, 15+ (x-10)=23

   => x-10= 8

   => x= 8+ 10

   => x=18

   Vậy x=18

   ————————-

   d, 11-(-53+x)=97

   => 11+53-x=97

   => 64-x=97

   => x= -33

   Vậy x=-33

   —————————–

   e, 61+ (x-23)=91

   => 61+ x-23=91

   => x+ (61-23)=91

   => x+ 38=91

   => x= 91-38

   => x= 53

   Vậy x=53

    

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