a, -5/19 + 3/19 < x/19 $\leq$ 13/19 + -11/19 b, -7/8 + 5/6 < x/24 $\leq$ 5/8 + -5/12 10/07/2021 Bởi Alaia a, -5/19 + 3/19 < x/19 $\leq$ 13/19 + -11/19 b, -7/8 + 5/6 < x/24 $\leq$ 5/8 + -5/12
a) `-5/19+3/19<x/19≤13/19+-11/19` `⇒ -2/19<x≤2/19` `⇒ x={-1; 0; 1; 2}` b) `-7/8+5/6<x/24≤5/8+-5/12` `⇒ -1/24<x≤5/24` `⇒ x={0; 1; 2; 3; 4; 5} Bình luận
a, Ta có: $\frac{-5}{19}+$ $\frac{3}{19}<$ $\frac{x}{19}<$ $\frac{13}{19}+$ $\frac{-11}{19}$ ⇒$\frac{-2}{19}<$ $\frac{x}{19}<$ $\frac{2}{19}$ ⇒x∈{-1;0;1} b, Ta có: $\frac{-7}{8}+$ $\frac{5}{6}<$ $\frac{x}{24}<$ $\frac{5}{8}+$ $\frac{-5}{12}$ ⇒$\frac{-1}{24}<$ $\frac{x}{24}<$ $\frac{5}{24}$ ⇒x∈{0;1;2;3;4} Bình luận
a) `-5/19+3/19<x/19≤13/19+-11/19`
`⇒ -2/19<x≤2/19`
`⇒ x={-1; 0; 1; 2}`
b) `-7/8+5/6<x/24≤5/8+-5/12`
`⇒ -1/24<x≤5/24`
`⇒ x={0; 1; 2; 3; 4; 5}
a, Ta có: $\frac{-5}{19}+$ $\frac{3}{19}<$ $\frac{x}{19}<$ $\frac{13}{19}+$ $\frac{-11}{19}$
⇒$\frac{-2}{19}<$ $\frac{x}{19}<$ $\frac{2}{19}$
⇒x∈{-1;0;1}
b, Ta có: $\frac{-7}{8}+$ $\frac{5}{6}<$ $\frac{x}{24}<$ $\frac{5}{8}+$ $\frac{-5}{12}$
⇒$\frac{-1}{24}<$ $\frac{x}{24}<$ $\frac{5}{24}$
⇒x∈{0;1;2;3;4}