a) (5x-2y)(x^2-xy+1). (x-1)(x+1)(x+2) c)1/2x^2 y^2(2x+y)(2x-y) 28/09/2021 Bởi Cora a) (5x-2y)(x^2-xy+1). (x-1)(x+1)(x+2) c)1/2x^2 y^2(2x+y)(2x-y)
\(\begin{array}{l} +)\;(5x – 2y)({x^2} – xy + 1)\\ = 5x.({x^2} – xy + 1) – 2y({x^2} – xy + 1)\\ = 5{x^3} – 5{x^2}y + 5x – 2{x^2}y + 2x{y^2} – 2\\ = 5{x^3} – 7{x^2}y + 5x + 2x{y^2} – 2\\ +)\;(x – 1)(x + 1)(x + 2)\\ = ({x^2} – 1)(x – 2)\\ = {x^2}(x – 2) – 1.(x – 2)\\ = {x^3} – 2{x^2} – x + 2 \end{array}\) Bình luận
\(\begin{array}{l}
+)\;(5x – 2y)({x^2} – xy + 1)\\
= 5x.({x^2} – xy + 1) – 2y({x^2} – xy + 1)\\
= 5{x^3} – 5{x^2}y + 5x – 2{x^2}y + 2x{y^2} – 2\\
= 5{x^3} – 7{x^2}y + 5x + 2x{y^2} – 2\\
+)\;(x – 1)(x + 1)(x + 2)\\
= ({x^2} – 1)(x – 2)\\
= {x^2}(x – 2) – 1.(x – 2)\\
= {x^3} – 2{x^2} – x + 2
\end{array}\)