a) 5(3x-2) – 6x=-28 b) 7-3x=9=24(x-2)+10(5-x) c) 2(13+3x)-5(6+2x)=-32 d) (2x+12)(2x+12)(-3x-9)=0 19/07/2021 Bởi Josephine a) 5(3x-2) – 6x=-28 b) 7-3x=9=24(x-2)+10(5-x) c) 2(13+3x)-5(6+2x)=-32 d) (2x+12)(2x+12)(-3x-9)=0
Bạn tham khảo nha: a) 5(3x-2)-6x=-28 ⇔15x-10-6x=-28 ⇔15x-6x =-28+10 ⇔9x =-18 ⇔ x =-18:9 ⇔ x =-2 Vậy x=-2 b) 7-3x-9=24(x-2)+10(5-x) ⇔7-3x-9=24x-48+50-10x ⇔10x-3x-24x=-48+50-7+9 ⇔-17x =4 ⇔ x =-$\frac{4}{17}$ Vậy x=-$\frac{4}{17}$ c) 2(13+3x)-5(6+2x)=-32 ⇔26+6x-30-10x =-32 ⇔ 6x-10x =-32-26+30 ⇔ -4x =-28 ⇔ x =(-28):(-4) ⇔ x =7 Vậy x=7 d) (2x+12)(2x+12)(-3x-9)=0 ⇔\(\left[ \begin{array}{l}2x+12=0\\-3x-9=0\end{array} \right.\)⇔\(\left[ \begin{array}{l}2x=-12\\-3x=9\end{array} \right.\)⇔\(\left[ \begin{array}{l}x=-12:2\\x=9:(-3)\end{array} \right.\)⇔\(\left[ \begin{array}{l}x=-6\\x=-3\end{array} \right.\) Vậy x=-6; x=-3. Bình luận
Đáp án:a) x=-2 b) x= \(\frac{-4}{17}\) c)x=7 d)x=-6; x=-3 Giải thích các bước giải: a)5(3x-2)-6x=-28 => 15x-10-6x=-28 => 9x=-18 => x=-2 B) 7-3x-9=24(x-2)+10(5-x) =>24x-48+50-10x=7-3x-9 => 17x=-4=>x= \(\frac{-4}{17}\) c) 2(13+3x)-5(6+2x)=-32 => 26+6x-30-10x=-32 =>-4x=-28 => x=7 d) (2x+12)(2x+12)(-3x-9)=0 Cho 2x+12=0=> 2x=-12=> x=-6 -3x-9=0=> -3x=9=> x=-3 Vậy có 2 nghiệm x=-6; x=-3 Bình luận
Bạn tham khảo nha:
a) 5(3x-2)-6x=-28
⇔15x-10-6x=-28
⇔15x-6x =-28+10
⇔9x =-18
⇔ x =-18:9
⇔ x =-2
Vậy x=-2
b) 7-3x-9=24(x-2)+10(5-x)
⇔7-3x-9=24x-48+50-10x
⇔10x-3x-24x=-48+50-7+9
⇔-17x =4
⇔ x =-$\frac{4}{17}$
Vậy x=-$\frac{4}{17}$
c) 2(13+3x)-5(6+2x)=-32
⇔26+6x-30-10x =-32
⇔ 6x-10x =-32-26+30
⇔ -4x =-28
⇔ x =(-28):(-4)
⇔ x =7
Vậy x=7
d) (2x+12)(2x+12)(-3x-9)=0
⇔\(\left[ \begin{array}{l}2x+12=0\\-3x-9=0\end{array} \right.\)⇔\(\left[ \begin{array}{l}2x=-12\\-3x=9\end{array} \right.\)⇔\(\left[ \begin{array}{l}x=-12:2\\x=9:(-3)\end{array} \right.\)⇔\(\left[ \begin{array}{l}x=-6\\x=-3\end{array} \right.\)
Vậy x=-6; x=-3.
Đáp án:a) x=-2
b) x= \(\frac{-4}{17}\)
c)x=7
d)x=-6; x=-3
Giải thích các bước giải:
a)5(3x-2)-6x=-28 => 15x-10-6x=-28 => 9x=-18
=> x=-2
B) 7-3x-9=24(x-2)+10(5-x)
=>24x-48+50-10x=7-3x-9
=> 17x=-4=>x= \(\frac{-4}{17}\)
c) 2(13+3x)-5(6+2x)=-32
=> 26+6x-30-10x=-32 =>-4x=-28 => x=7
d) (2x+12)(2x+12)(-3x-9)=0
Cho 2x+12=0=> 2x=-12=> x=-6
-3x-9=0=> -3x=9=> x=-3
Vậy có 2 nghiệm x=-6; x=-3