a)(5.3^21+4.3^22):(3^19.5^2-3^19.2^30) b)(2x+1).(y-5)=12 c)(2x+1).(y^2-5)=12

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1. Giải thích các bước giải:

   2x+1 là số tự nhiên lẻ nên ta có:

   \(\begin{array}{l}
   b,\\
   \left( {2x + 1} \right)\left( {y – 5} \right) = 12\\
    \Leftrightarrow \left[ \begin{array}{l}
   \left\{ \begin{array}{l}
   2x + 1 = 1\\
   y – 5 = 12
   \end{array} \right.\\
   \left\{ \begin{array}{l}
   2x + 1 = 3\\
   y – 5 = 4
   \end{array} \right.
   \end{array} \right. \Leftrightarrow \left[ \begin{array}{l}
   \left\{ \begin{array}{l}
   x = 0\\
   y = 17
   \end{array} \right.\\
   \left\{ \begin{array}{l}
   x = 1\\
   y = 9
   \end{array} \right.
   \end{array} \right.\\
   b,\\
   \left( {2x + 1} \right)\left( {{y^2} – 5} \right) = 12\\
    \Leftrightarrow \left[ \begin{array}{l}
   \left\{ \begin{array}{l}
   2x + 1 = 1\\
   {y^2} – 5 = 12
   \end{array} \right.\\
   \left\{ \begin{array}{l}
   2x + 1 = 3\\
   {y^2} – 5 = 4
   \end{array} \right.
   \end{array} \right. \Leftrightarrow \left[ \begin{array}{l}
   \left\{ \begin{array}{l}
   x = 0\\
   {y^2} = 17
   \end{array} \right.\\
   \left\{ \begin{array}{l}
   x = 1\\
   {y^2} = 9
   \end{array} \right.
   \end{array} \right. \Leftrightarrow \left\{ \begin{array}{l}
   x = 1\\
   y = 3
   \end{array} \right.
   \end{array}\)

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