a) [6.(-1/3)mũ2-3.(-1/3)+1]:(-1/3-1) b) (2/3)mũ3.(-3/4)mũ2.(-1)mũ2003 phần (2/5)mũ2.(-5/12)mũ3 06/11/2021 Bởi Samantha a) [6.(-1/3)mũ2-3.(-1/3)+1]:(-1/3-1) b) (2/3)mũ3.(-3/4)mũ2.(-1)mũ2003 phần (2/5)mũ2.(-5/12)mũ3
Cách giải:$a,[6.(\dfrac{-1}{3})^{3}-3.(\dfrac{-1}{3})]:(\dfrac{-1}{3}-1)$ $=[6.\dfrac{-1}{27}+1]:\dfrac{-4}{3}$ $=\dfrac{7}{9}:\dfrac{-4}{3}$ $=\dfrac{-7}{12}$ $b,(\dfrac{2}{3})^{3}.(\dfrac{-3}{4})^{2}.\dfrac{(-1)^{2003}}{(\dfrac{2}{5})^{2}.(\dfrac{-5}{12})^{3}}$ $=\dfrac{8}{27}.\dfrac{9}{16}.\dfrac{1}{(\dfrac{2}{5}.\dfrac{5}{2})^{2}.\dfrac{5}{12}}$ $=\dfrac{1}{6}.\dfrac{1}{\dfrac{5}{12}}$ $=\dfrac{1}{6}.\dfrac{12}{5}$ $=\dfrac{2}{5}$ Bình luận
`a)[6.(-1/3)^2-3(-1/3)+1]:(-1/3-1)` `=[6.1/9+1+1):(-4/3)` `=8/3 . -3/4` `=-2` `b)(2/3)^3 . (-3/4)^2 . (-1)^(2003):(2/5)^2 . (-5/12)^3` `=8/27 . 9/16 . (-1):(-5/432)` `=1/6 . 432/5` `=72/5` Bình luận
Cách giải:
$a,[6.(\dfrac{-1}{3})^{3}-3.(\dfrac{-1}{3})]:(\dfrac{-1}{3}-1)$
$=[6.\dfrac{-1}{27}+1]:\dfrac{-4}{3}$
$=\dfrac{7}{9}:\dfrac{-4}{3}$
$=\dfrac{-7}{12}$
$b,(\dfrac{2}{3})^{3}.(\dfrac{-3}{4})^{2}.\dfrac{(-1)^{2003}}{(\dfrac{2}{5})^{2}.(\dfrac{-5}{12})^{3}}$
$=\dfrac{8}{27}.\dfrac{9}{16}.\dfrac{1}{(\dfrac{2}{5}.\dfrac{5}{2})^{2}.\dfrac{5}{12}}$
$=\dfrac{1}{6}.\dfrac{1}{\dfrac{5}{12}}$
$=\dfrac{1}{6}.\dfrac{12}{5}$
$=\dfrac{2}{5}$
`a)[6.(-1/3)^2-3(-1/3)+1]:(-1/3-1)`
`=[6.1/9+1+1):(-4/3)`
`=8/3 . -3/4`
`=-2`
`b)(2/3)^3 . (-3/4)^2 . (-1)^(2003):(2/5)^2 . (-5/12)^3`
`=8/27 . 9/16 . (-1):(-5/432)`
`=1/6 . 432/5`
`=72/5`