a) [6.(-1/3)mũ2 – 3.(-1/3)+1]:(-1/3-1) b) (2/3)mũ3.(-3/4)mũ2.(-1)mũ2003 phần (2/5)mũ2.(-5/12)mũ3

0 bình luận về “a) [6.(-1/3)mũ2 – 3.(-1/3)+1]:(-1/3-1) b) (2/3)mũ3.(-3/4)mũ2.(-1)mũ2003 phần (2/5)mũ2.(-5/12)mũ3”

1. Bài làm :

   a, `[6.(- 1/3)^2 – 3 . (- 1/3) + 1] : ( – 1/3 – 1 )`

   `= [6. 1/9 – (-1) + 1] : (- 4/3)`

   `= [2/3 – (-1) + 1] : ( – 4/3)`

   `= 8/3 : (- 4/3)`

   `= -2`

   b, `{(2/3)^3 . (- 3/4 )^2 . (-1)^(2003)}/{(2/5)^2 . (- 5/12)^3}`
   

   `= {(2/3)^3 . (3/4 )^2 . (-1)}/{(2/5)^2 . (- 5/12)^3}`

   `= {(2/3)^3 . (3/4 )^2}/{(2/5)^2 . (- 5/12)^3}`

   `=` $\dfrac{\dfrac{2^3 . 3^2}{3^3 . 4^2}}{\dfrac{2^2 . 5^3}{5^2 . 12^3}}$ 

   `= {2^3 . 3^2 . 5^2 . 12^3}/{3^3 . 4^2 . 2^2 . 5^3}`

   `= {2^3 . 3^2 . 5^2 . 2^6 . 3^3}/{3^3 . 4^2 . 2^2 . 5^3}`

   `= {2^9 . 3^5 . 5^2}/{3^3 . 2^6 . 5^3}`

   `= {2^3 . 3^2}/{5}`

   `= (72)/(5)`

    

   Bình luận