A) ( 7 + 7/5 – 2/3 ) – ( 4 + 4/5 + 3/8 ) + ( 3 – 3/5 + 2/3 + 3/8 ) = B) 15/12 + 5/13 – 3/12 – 18/13 = C) 13/25 + 6/41 – 38/25 + 35/41 – 1/2 = Cần Gấp

0 bình luận về “A) ( 7 + 7/5 – 2/3 ) – ( 4 + 4/5 + 3/8 ) + ( 3 – 3/5 + 2/3 + 3/8 ) = B) 15/12 + 5/13 – 3/12 – 18/13 = C) 13/25 + 6/41 – 38/25 + 35/41 – 1/2 = Cần Gấp”

1. A) ( 7 + $\frac{7}{5}$  – $\frac{2}{3}$  ) – ( 4 + $\frac{4}{5}$  + $\frac{3}{8}$  ) + ( 3 – $\frac{3}{5}$  + $\frac{2}{3}$  + $\frac{3}{8}$  ) 

   =  7 + $\frac{7}{5}$  – $\frac{2}{3}$   –  4 – $\frac{4}{5}$  – $\frac{3}{8}$   +  3 – $\frac{3}{5}$  + $\frac{2}{3}$  + $\frac{3}{8}$  

   = (7 – 4 + 3) + ($\frac{7}{5}$ – $\frac{4}{5}$ – $\frac{3}{5}$) + (- $\frac{2}{3}$ + $\frac{2}{3}$) + (- $\frac{3}{8}$ + $\frac{3}{8}$ )

   = 6 

   B) $\frac{15}{12}$  + $\frac{5}{13}$  – $\frac{3}{12}$  – $\frac{18}{13}$  

   = ($\frac{15}{12}$ – $\frac{3}{12}$) + ($\frac{5}{13}$ – $\frac{18}{13}$)

   = 1 – 1

   = 0 

   C) $\frac{13}{25}$  + $\frac{6}{41}$ – $\frac{38}{25}$ + $\frac{35}{41}$ – $\frac{1}{2}$

   = ($\frac{13}{25}$ – $\frac{38}{25}$) + ($\frac{6}{41}$ + $\frac{35}{41}$) – $\frac{1}{2}$

   = -1 + 1 – $\frac{1}{2}$

   = – $\frac{1}{2}$

    

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