Toán a, 9/25.x⁴ – 1/4 b, 4x ²+ 4x-1/4 áp dụng hẳng đẳng thức 09/07/2021 By Aubrey a, 9/25.x⁴ – 1/4 b, 4x ²+ 4x-1/4 áp dụng hẳng đẳng thức
a) $\frac{9}{25}.x^{4}-$$\frac{1}{4}$ =$(\frac{3}{5}.x^{2})^{2}-(\frac{1}{2})^{2}$ =$(\frac{3}{5}x-\frac{1}{2})$.$(\frac{3}{5}x+$$\frac{1}{2})$ b) $4x^{2} + 4x + 1$= $(2x)^{2} + 2.2x + 1^{2}$= $(2x + 1)^{2}$ HOK TỐT Trả lời
???? $a$ $)$ $\frac{9}{25}$ $x⁴$ $-$ $\frac{1}{4}$ $=$ ( $\frac{3}{5}$ $x²$ – $\frac{1}{2}$) $.$ ( $\frac{3}{5}$ $x²$ + $\frac{1}{2}$) $b$ $)$ $4x²$ + $4x$ $+$ $1$ = $( $2x$ $+$ $1$ )²$ Trả lời
a) $\frac{9}{25}.x^{4}-$$\frac{1}{4}$
=$(\frac{3}{5}.x^{2})^{2}-(\frac{1}{2})^{2}$
=$(\frac{3}{5}x-\frac{1}{2})$.$(\frac{3}{5}x+$$\frac{1}{2})$
b) $4x^{2} + 4x + 1$
= $(2x)^{2} + 2.2x + 1^{2}$
= $(2x + 1)^{2}$
HOK TỐT
????
$a$ $)$
$\frac{9}{25}$ $x⁴$ $-$ $\frac{1}{4}$
$=$ ( $\frac{3}{5}$ $x²$ – $\frac{1}{2}$) $.$ ( $\frac{3}{5}$ $x²$ + $\frac{1}{2}$)
$b$ $)$
$4x²$ + $4x$ $+$ $1$
= $( $2x$ $+$ $1$ )²$