a) √ x + 9 = 7 b) 4 √ 2 x + 3 − √ 8 x + 12 + 1 3 √ 18 x + 27 = 15 c) √ x + 3 + 4 √ x − 1 + √ x + 8 − 6 √ x − 1 = 5 07/09/2021 Bởi Alexandra a) √ x + 9 = 7 b) 4 √ 2 x + 3 − √ 8 x + 12 + 1 3 √ 18 x + 27 = 15 c) √ x + 3 + 4 √ x − 1 + √ x + 8 − 6 √ x − 1 = 5
Đáp án: a) x=40 b) x=-3/2 c) x=1 Giải thích các bước giải: $\begin{array}{l} a)\sqrt {x + 9} = 7dkxd:x \ge – 9\\ \Rightarrow x + 9 = 49\\ \Rightarrow x = 40\,\left( {tmdk} \right)\\ b)4\sqrt {2x + 3} – \sqrt {8x + 12} + 13\sqrt {18x + 27} = 0\left( {dkxdx \ge \frac{{ – 3}}{2}} \right)\\ \Rightarrow 4\sqrt {2x + 3} – 2\sqrt {2x + 3} + 13.3.\sqrt {2x + 3} = 0\\ \Rightarrow 41\sqrt {2x + 3} = 0\\ \Rightarrow \sqrt {2x + 3} = 0\\ \Rightarrow 2x + 3 = 0\\ \Rightarrow x = \frac{{ – 3}}{2}\left( {tmdk} \right)\\ c)\sqrt {x + 3} + 4\sqrt {x – 1} + \sqrt {x + 8} – 6\sqrt {x – 1} = 5\\ \Rightarrow x = 1 \end{array}$ Bình luận
Đáp án:
a) x=40
b) x=-3/2
c) x=1
Giải thích các bước giải:
$\begin{array}{l}
a)\sqrt {x + 9} = 7dkxd:x \ge – 9\\
\Rightarrow x + 9 = 49\\
\Rightarrow x = 40\,\left( {tmdk} \right)\\
b)4\sqrt {2x + 3} – \sqrt {8x + 12} + 13\sqrt {18x + 27} = 0\left( {dkxdx \ge \frac{{ – 3}}{2}} \right)\\
\Rightarrow 4\sqrt {2x + 3} – 2\sqrt {2x + 3} + 13.3.\sqrt {2x + 3} = 0\\
\Rightarrow 41\sqrt {2x + 3} = 0\\
\Rightarrow \sqrt {2x + 3} = 0\\
\Rightarrow 2x + 3 = 0\\
\Rightarrow x = \frac{{ – 3}}{2}\left( {tmdk} \right)\\
c)\sqrt {x + 3} + 4\sqrt {x – 1} + \sqrt {x + 8} – 6\sqrt {x – 1} = 5\\
\Rightarrow x = 1
\end{array}$