a.C2H4->C2H5OH->CH3COOH->CH3COOC2H5->CH3COOH->(CH3COO)2Ca
b.C2H4->C2H5OH->CH3COOH->CH3COOC2H5->CH3COONa->C2H5ONa
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Giúp mik với đang cần gấp
a.C2H4->C2H5OH->CH3COOH->CH3COOC2H5->CH3COOH->(CH3COO)2Ca
b.C2H4->C2H5OH->CH3COOH->CH3COOC2H5->CH3COONa->C2H5ONa
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Giúp mik với đang cần gấp
a,
$C_2H_4+H_2O\buildrel{{H^+, t^o}}\over\to C_2H_5OH$
$C_2H_5OH+O_2\buildrel{{\text{men giấm}}}\over\to CH_3COOH+H_2O$
$CH_3COOH+C_2H_5OH\buildrel{{H_2SO_4, t^o}}\over\rightleftharpoons CH_3COOC_2H_5+H_2O$
$CH_3COOC_2H_5+H_2O\buildrel{{t^o}}\over\rightleftharpoons CH_3COOH+C_2H_5OH$
$2CH_3COOH+Ca\to (CH_3COO)_2Ca+H_2$
b,
$C_2H_4+H_2O\buildrel{{H^+, t^o}}\over\to C_2H_5OH$
$C_2H_5OH+O_2\buildrel{{\text{men giấm}}}\over\to CH_3COOH+H_2O$
$CH_3COOH+C_2H_5OH\buildrel{{H_2SO_4, t^o}}\over\rightleftharpoons CH_3COOC_2H_5+H_2O$
$CH_3COOC_2H_5+NaOH \buildrel{{t^o}}\over\to CH_3COONa+C_2H_5OH$
$2C_2H_5OH+2Na\to 2C_2H_5ONa+H_2$
Đáp án:
Giải thích các bước giải:
a.
$C_2H_4 + H2O \xrightarrow{xt,t^o} C_2H_5OH$
$C_2H_5OH + O_2 \xrightarrow{xt,t^o} CH_3COOH + H_2O$
$CH_3COOH + C_2H_5OH ⇄ CH_3COOC_2H_5 + H_2O$
$CH_3COOC_2H_5 + H_2O⇄ CH_3COOH + C_2H_5OH$
$2CH_3COOH + Ca → (CH_3COO)_2Ca + H_2$
b.
$C_2H_4 + H2O \xrightarrow{xt,t^o} C_2H_5OH$
$C_2H_5OH + O_2 \xrightarrow{xt,t^o} CH_3COOH + H_2O$
$CH_3COOH + C_2H_5OH ⇄ CH_3COOC_2H_5 + H_2O$
$CH_3COOC_2H_5 + NaOH → CH_3COONa + C_2H_5OH$
$2C_2H_5OH + 2Na → 2C_2H_5ONa + H_2 $