a)$\frac{2}{3}$.x+$\frac{1}{5}$=$\frac{7}{10}$-x b)3$\frac{1}{3}$x+16$\frac{3}{4}$=-13,25 c)(3$\frac{4}{5}$-2.x).1$\frac{1}{3}$=5$\frac{5}{7}$

0 bình luận về “a)$\frac{2}{3}$.x+$\frac{1}{5}$=$\frac{7}{10}$-x b)3$\frac{1}{3}$x+16$\frac{3}{4}$=-13,25 c)(3$\frac{4}{5}$-2.x).1$\frac{1}{3}$=5$\frac{5}{7}$”

1. Đáp án:

   $a/$ `2/3x + 1/5 = 7/10 – x`

   `-> 2/3x + 1/5 – 7/10 + x = 0`

   `-> (2/3x + x) + (1/5 – 7/10) = 0`

   `-> 5/3x – 1/2 = 0`

   `-> 5/3x = 1/2`

   `-> x = 3/10`

   `text{Vậy}` `x = 3/10`

   $b/$ `3 1/3x + 16 3/4 = -13,25`

   `-> 10/3x + 67/4= -13,25`

   `-> 10/3x = -30`

   `-> x = -9`

   `text{Vậy}` `x = -9`

   $c/$ `(3 4/5 – 2x) . 1 1/3 = 5 5/7`

   `-> (19/5 – 2x) . 4/3 = 40/7`

   `-> 19/5 – 2x = 30/7`

   `-> 2x = (-17)/35`

   `-> x = (-17)/70`

   `text{Vậy}` `x = (-17)/70`

    

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