a)x+$\frac{3}{22}$=$\frac{27}{121}$.$\frac{11}{9}$
b)$\frac{1}{5}$:x=$\frac{1}{5}$-$\frac{1}{7}$
c)(-2$\frac{2}{11}$):x-4$\frac{2}{3}$=$\frac{5}{6}$
d)3$\frac{1}{3}$x+16$\frac{3}{4}$=-13,25
a)x+$\frac{3}{22}$=$\frac{27}{121}$.$\frac{11}{9}$
b)$\frac{1}{5}$:x=$\frac{1}{5}$-$\frac{1}{7}$
c)(-2$\frac{2}{11}$):x-4$\frac{2}{3}$=$\frac{5}{6}$
d)3$\frac{1}{3}$x+16$\frac{3}{4}$=-13,25
Đáp án:
a) `x=3/22`
b) `x=7/2`
c) `x=-48/121`
d) `x=-9`
Giải thích các bước giải:
a) `x+3/22=27/121 . 11/9`
`to x+3/22=3/11`
`to x=3/11-3/22`
`to x=3/22`
b) `1/5:x=1/5-1/7`
`to 1/5:x=2/35`
`to x=1/5 : 2/35`
`to x=7/2`
c) `(-2 2/11):x-4 2/3=5/6`
`to (-24/11):x-14/3=5/6`
`to (-24/11):x=5/6+14/3`
`to (-24/11):x=11/2`
`to x=(-24/11):11/2`
`to x=-48/121`
d) `3 1/3x+16 3/4=-13,25`
`to 10/3x+67/4=-13,25`
`to 10/3x=-13,25-67/4`
`to 10/3x=-30`
`to x=(-30):10/3`
`to x=-9`
Đáp án:
d) x=-9
Giải thích các bước giải:
\(\begin{array}{l}
a)x + \dfrac{3}{{22}} = \dfrac{27}{{121}}.\dfrac{{11}}{9}\\
\to x + \dfrac{3}{{22}} = \dfrac{3}{{11}}\\
\to x = \dfrac{3}{{11}} – \dfrac{3}{{22}}\\
\to x = \dfrac{{3}}{{22}}\\
b)DK:x \ne 0\\
\dfrac{1}{5}:x = \dfrac{1}{5} – \dfrac{1}{7}\\
\to \dfrac{1}{{5x}} = \dfrac{2}{{35}}\\
\to 5x = \dfrac{{35}}{2}\\
\to x = \dfrac{7}{2}\\
c)DK:x \ne 0\\
– \dfrac{{24}}{{11}}:x – \dfrac{{14}}{3} = \dfrac{5}{6}\\
\to – \dfrac{{24}}{{11x}} = \dfrac{5}{6} + \dfrac{{14}}{3}\\
\to – \dfrac{{24}}{{11x}} = \dfrac{{11}}{2}\\
\to x = – \dfrac{{48}}{{121}}\\
d)\dfrac{{10}}{3}x + \dfrac{{67}}{4} = – \dfrac{{53}}{4}\\
\to \dfrac{{10}}{3}x = – 30\\
\to x = – 9
\end{array}\)