a, $\frac{4}{45}$ – ( $\frac{4}{5}$ +x ) = $\frac{3}{7}$
b, ( 7.x – 1) . ( 3.x – $\frac{1}{2}$ ) = 0
c, | 3x – 2 | – 14 = $\frac{1}{3}$
d, $\frac{1}{25}$ . 125 mũ x = 5 mũ x
a, $\frac{4}{45}$ – ( $\frac{4}{5}$ +x ) = $\frac{3}{7}$ b, ( 7.x – 1) . ( 3.x – $\frac{1}{2}$ ) = 0 c, | 3x – 2 | – 14 = $\frac{1}{3}$ d, $\frac{
By Alexandra
`a) => 4/5+x=4/45-3/7=-107/315`
`=> x=-107/315-4/5`
`=> x=-359/315`
`b) => 7x-1=0` hoặc `3x-1/2=0`
`=> 7x=1` hoặc `3x=1/2`
`=> x=1/7` hoặc `x=1/6`
`c)=> |3x-2|=1/3+14=43/3`
`=> 3x-2=43/3` hoặc `3x-2=-43/3`
`=> 3x=49/3` hoặc `3x=-37/3`
`=> x=49/9` hoặc `x=-37/9`
`d) => 5^(-2). (5^3)^x=5^x`
`=> 5^(-2). 5^(3x)=5^x`
`=> 5^(-2+3x)=5^x`
`=> -2+3x=x`
`=> 3x-x=2`
`=> 2x=2`
`=> x=1`
a)⇒45+x=445−37=−107315
⇒45+x=445-37=-107315
⇒x=−359315
b)⇒7x−1=0hoặc 3x−12=0
⇒7x=1hoặc 3x=12
⇒x=17 hoặc x=16
c)⇒|3x−2|=13+14=433c)
⇒3x-2=433 hoặc 3x-2=-433
⇒3x=493 hoặc 3x=-373
⇒x=499 hoặc x=-379
d)⇒5−2.(53)x=5x
⇒5−2.53x=5x
⇒5−2+3x=5x
⇒−2+3x=x
⇒3x−x=2
⇒2x=2
⇒x=1