A rectangular garden has length of x (dm) and area of 252 $dm^{2}$. If the width is 5 cm less than one – third of the length, then the perimeter of this garden is ……. dm
A rectangular garden has length of x (dm) and area of 252 $dm^{2}$. If the width is 5 cm less than one – third of the length, then the perimeter of this garden is ……. dm
Đáp án:
Giải thích các bước giải:
the width of the garden is x/3-5
because area of this garden is 252 , we have
x (x/3-5) = 252
1/3x ^2 – 5x – 252 =0
=> x = 36 dm
the width of the garden
36/3-5 =7 (dm )
the perimeter (36+7)x2 =84 dm
The width of the garden is: `x/3` `-` `5` ( dm )
According to the threads we have:
`x(x/3-5)“=`252`
`⇔` `1/3x^2“-“5x“-“252“=“0`
`⇔` `x=36` ( dm )
`⇔` The width of the garden is: `36/3“-“5“=“12“-“5“=“7` ( dm )
`⇔` The perimeter of this garden is: `(36+7).2“=“84` ( dm )
@ chú lân