AI giúp mình với: Bài 8: Tính nhanh tổng sau: S = 1/20 + 1/44 + 1/77 + … + 1/3080 12/07/2021 Bởi Aubrey AI giúp mình với: Bài 8: Tính nhanh tổng sau: S = 1/20 + 1/44 + 1/77 + … + 1/3080
Đáp án: `S=1/8` Giải thích các bước giải: `S=1/20+1/44+1/77+…+1/3080` `=>S/2=1/40+1/88+1/154+…+1/6160` `=>S/2=1/5.8+1/8.11+1/11.14+…+1/77.80` `=>(3S)/2=3/5.8+3/8.11+3/11.14+…+3/77.80` `=>(3S)/2=1/5-1/8+1/8-1/11+1/11-1/14+…+1/77-1/80` `=>(3S)/2=1/5-1/80` `=>(3S)/2=3/16` `=>3S=3/16*2` `=>3S=3/8` `=>S=3/8÷3` `=>S=1/8` Vậy `S=1/8`. Bình luận
`**) (b – a)/(a. b) = 1/a – 1/b` `S = 1/20 + 1/44 + 1/77 + … + 1/3080` `=> S = 2. 1/2. (1/20 + 1/44 + 1/77 + … + 1/3080)` `=> S = 2. (1/40 + 1/88 + 1/154 + … + 1/6160)` `=> S = 2. 1/3. 3. (1/(5. 8) + 1/(8. 11) + 1/(11. 13) + … + 1/(77. 80))` `=> S = 2. 1/3. (3/(5. 8) + 3/(8. 11) + 3/(11. 13) + … + 3/(77. 80))` `=> S = 2/3. (1/5 – 1/8 + 1/8 – 1/11 + 1/11 – 1/13 + … + 1/77 – 1/80)` `=> S = 2/3. (1/5 – 1/80)` `=> S = 2/3. 3/16` `=> S = 1/8` Vậy `S = 1/8` Bình luận
Đáp án:
`S=1/8`
Giải thích các bước giải:
`S=1/20+1/44+1/77+…+1/3080`
`=>S/2=1/40+1/88+1/154+…+1/6160`
`=>S/2=1/5.8+1/8.11+1/11.14+…+1/77.80`
`=>(3S)/2=3/5.8+3/8.11+3/11.14+…+3/77.80`
`=>(3S)/2=1/5-1/8+1/8-1/11+1/11-1/14+…+1/77-1/80`
`=>(3S)/2=1/5-1/80`
`=>(3S)/2=3/16`
`=>3S=3/16*2`
`=>3S=3/8`
`=>S=3/8÷3`
`=>S=1/8`
Vậy `S=1/8`.
`**) (b – a)/(a. b) = 1/a – 1/b`
`S = 1/20 + 1/44 + 1/77 + … + 1/3080`
`=> S = 2. 1/2. (1/20 + 1/44 + 1/77 + … + 1/3080)`
`=> S = 2. (1/40 + 1/88 + 1/154 + … + 1/6160)`
`=> S = 2. 1/3. 3. (1/(5. 8) + 1/(8. 11) + 1/(11. 13) + … + 1/(77. 80))`
`=> S = 2. 1/3. (3/(5. 8) + 3/(8. 11) + 3/(11. 13) + … + 3/(77. 80))`
`=> S = 2/3. (1/5 – 1/8 + 1/8 – 1/11 + 1/11 – 1/13 + … + 1/77 – 1/80)`
`=> S = 2/3. (1/5 – 1/80)`
`=> S = 2/3. 3/16`
`=> S = 1/8`
Vậy `S = 1/8`