b) x+2/10 + x+3/3 + x+4/4 +6=0 c)x^2+99/ +x^2+100/101=x^2+101/102+x^2+102/103 31/07/2021 Bởi Natalia b) x+2/10 + x+3/3 + x+4/4 +6=0 c)x^2+99/ +x^2+100/101=x^2+101/102+x^2+102/103
b) x+2/10 + x+3/3 + x+4/4 +6=0
<=>x+1/5+ x+1 + x+1 +6=0
<=>x+x+x=8,2
<=>x=8,2/3=8,2/3