Bài 1: a) 1/7 . x = -3/2 b) 2/15 – x = -7/45 c) 2 . ( 3/24 – x ) = 3/4 = 5/12 13/08/2021 Bởi Alice Bài 1: a) 1/7 . x = -3/2 b) 2/15 – x = -7/45 c) 2 . ( 3/24 – x ) = 3/4 = 5/12
Đáp án: a/$x=\frac{-21}{2}$ b/$x=\frac{13}{45}$ c/$x = \frac{7}{24}$ Giải thích các bước giải: a/$\frac{1}{7}.x=\frac{-3}{2}$ $x=\frac{-3}{2} : \frac{1}{7}$ $x=\frac{-21}{2}$ . b/$\frac{2}{15}-x=\frac{-7}{45}$ $x=\frac{2}{15}-\frac{-7}{45}$ $x=\frac{13}{45}$ . c/$2 . (\frac{3}{24} – x )+ \frac{3}{4}= \frac{5}{12}$ $2 . (\frac{3}{24} – x )= \frac{5}{12}- \frac{3}{4}$ $2 . (\frac{3}{24} – x ) = \frac{-1}{3}$ $\frac{3}{24} – x = \frac{-1}{3} :2$ $\frac{3}{24} – x = \frac{-1}{6}$ $x = \frac{3}{24} – \frac{-1}{6}$ $x = \frac{7}{24}$ $#minhthong2009$ Bình luận
Đáp án: a) `x=-21/2` b) `x=13/45` c) `x = 7/24` Giải thích các bước giải: a) `1/7 . x = -3/2` `to x = -3/2 : 1/7` `to x = -3/2 . 7` `to x = -21/2` Vậy `x = -21/2` b) `2/15 – x = -7/45` `to x = 2/15 – ( -7/45 )` `to x = 2/15 + 7/45` `to x = 6/45 + 7/45` `to x = 13/45` Vậy `x = 13/45` c) `2 . ( 3/24 – x ) + 3/4 = 5/12` `to 2 . ( 3/24 – x ) = 5/12 – 3/4` `to 2 . ( 3/24 – x ) = 5/12 – 9/12` `to 2 . ( 3/24 – x ) = -1/3` `to 3/24 – x = -1/3 : 2` `to 3/24 – x = -1/3 . 1/2` `to 3/24 – x = -1/6` `to x = 3/24 – ( -1/6 )` `to x = 3/24 + 1/6` `to x = 3/24 + 4/24` `to x = 7/24` Vậy `x = 7/24` Bình luận
Đáp án:
a/$x=\frac{-21}{2}$
b/$x=\frac{13}{45}$
c/$x = \frac{7}{24}$
Giải thích các bước giải:
a/$\frac{1}{7}.x=\frac{-3}{2}$
$x=\frac{-3}{2} : \frac{1}{7}$
$x=\frac{-21}{2}$
.
b/$\frac{2}{15}-x=\frac{-7}{45}$
$x=\frac{2}{15}-\frac{-7}{45}$
$x=\frac{13}{45}$
.
c/$2 . (\frac{3}{24} – x )+ \frac{3}{4}= \frac{5}{12}$
$2 . (\frac{3}{24} – x )= \frac{5}{12}- \frac{3}{4}$
$2 . (\frac{3}{24} – x ) = \frac{-1}{3}$
$\frac{3}{24} – x = \frac{-1}{3} :2$
$\frac{3}{24} – x = \frac{-1}{6}$
$x = \frac{3}{24} – \frac{-1}{6}$
$x = \frac{7}{24}$
$#minhthong2009$
Đáp án:
a) `x=-21/2`
b) `x=13/45`
c) `x = 7/24`
Giải thích các bước giải:
a) `1/7 . x = -3/2`
`to x = -3/2 : 1/7`
`to x = -3/2 . 7`
`to x = -21/2`
Vậy `x = -21/2`
b) `2/15 – x = -7/45`
`to x = 2/15 – ( -7/45 )`
`to x = 2/15 + 7/45`
`to x = 6/45 + 7/45`
`to x = 13/45`
Vậy `x = 13/45`
c) `2 . ( 3/24 – x ) + 3/4 = 5/12`
`to 2 . ( 3/24 – x ) = 5/12 – 3/4`
`to 2 . ( 3/24 – x ) = 5/12 – 9/12`
`to 2 . ( 3/24 – x ) = -1/3`
`to 3/24 – x = -1/3 : 2`
`to 3/24 – x = -1/3 . 1/2`
`to 3/24 – x = -1/6`
`to x = 3/24 – ( -1/6 )`
`to x = 3/24 + 1/6`
`to x = 3/24 + 4/24`
`to x = 7/24`
Vậy `x = 7/24`