bài 1 a x+28=15 b |x-2|=49 c 3x-51=2x+19 bài 2 a 25.(-4)+(7).(-9) b 2.(-5)^2+(-3)^3-19 c 1-2+3-4+ …-99-100+101 10/11/2021 Bởi Maya bài 1 a x+28=15 b |x-2|=49 c 3x-51=2x+19 bài 2 a 25.(-4)+(7).(-9) b 2.(-5)^2+(-3)^3-19 c 1-2+3-4+ …-99-100+101
Bài $1$ : a) $x + 28 = 15$ $x = 15 – 28 = -13$ b) $| x – 2 | = 49$ Vì $49 > 0 $ ⇒ $x – 2 = 49$ ⇔ $x = 49 + 2 = 51$ c) $3x – 51 = 2x + 19$ $x = 19 + 51 = 70$ Bài 2 : a) $25 . ( – 4 ) + 7 . ( – 9 )$ = $- 100 – 63$ = $- 163$ b) $2 . ( – 5 )² + ( – 3 )³ – 19$ = $2 . 25 – 27 – 19$ = $50 – 46$ = $4 $ c) $1 – 2 + 3 – 4 + . . . + 99 – 100 + 101$ = $( 1 – 2 ) + ( 3 – 4 ) + . . . + ( 99 – 100 ) +101$ = $- 1 – 1 – . . . – 1 + 101$ = $( – 1 ) . 50 + 101$ = $- 50 + 101 = 51$ Bình luận
Có gì sai thì comment hộ mk ở bình luận nha! Thank you mn
@sakuralinh
Bài $1$ :
a) $x + 28 = 15$
$x = 15 – 28 = -13$
b) $| x – 2 | = 49$
Vì $49 > 0 $
⇒ $x – 2 = 49$
⇔ $x = 49 + 2 = 51$
c) $3x – 51 = 2x + 19$
$x = 19 + 51 = 70$
Bài 2 :
a) $25 . ( – 4 ) + 7 . ( – 9 )$
= $- 100 – 63$
= $- 163$
b) $2 . ( – 5 )² + ( – 3 )³ – 19$
= $2 . 25 – 27 – 19$
= $50 – 46$
= $4 $
c) $1 – 2 + 3 – 4 + . . . + 99 – 100 + 101$
= $( 1 – 2 ) + ( 3 – 4 ) + . . . + ( 99 – 100 ) +101$
= $- 1 – 1 – . . . – 1 + 101$
= $( – 1 ) . 50 + 101$
= $- 50 + 101 = 51$