Bài 1 : a) 3 – ( – 6/7 )^0 + ( 1/2 )^2 b) ( -2 )^3 + 2^2 + ( – 1 )^20 + ( – 2 )^0 c) ( (3)^2)^2 – ( ( – 5 )^2)^2 –

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1. Đáp án:

   $a) 3 – (-\frac{6}{7})^{0} + (\frac{1}{2})^{2}$

   $= 3 – 1 + \frac{1}{4}$

   $= 2 + \frac{1}{4}$

   $= \frac{8}{4} + \frac{1}{4}$

   $= \frac{9}{4}$

   $= 2\frac{1}{4}$ 

   $b) (-2)^{3} + 2^{2} + (-1)^{20} + (-2)^{0}$

   $= -8 + 4 + 1 + 1$

   $= -2$

   $c) (3^{2})^{2} – [(-5)^{2}]^{2}$

   $= 81 – 625$

   $= -544$

   HỌC TỐT~~

   #NOCOPY

   #NOTHINGISIMPOSSIBLE

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2. Đáp án:

    

   Giải thích các bước giải:

   a) 3 – ( – 6/7 )^0 + ( 1/2 )^2

   = 3 – 1 + 1/2 x 1/2

   = 2 + 1/4

   = 8/4 + 1/4

   = 9/4

   b) ( -2 )^3 + 2^2 + ( – 1 )^20 + ( – 2 )^0

   = -8 + 4 + 1 + 1

   = -4 + 2 = -2

   c) ( (3)^2)^2 – ( ( – 5 )^2)^2 –

    = ( 9 ^2 ) – 25^2

   = 81 – 625 =-544

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