Bài 11 Tính a,15.141+53.15 b,17.85+15.17-1200 c,100:{250:[450-4.125-4.25)]}

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1. $\text{a,15.141+53.15}$

   =$\text{(15 x141+53)}$ 

   = $\text{15.194}$ 

   =$\text{2910}$ 

   $\text{b,17.85+15.17-1200}$

   =$\text{17 x(85+15)-1200}$ 

   =$\text{17 x 100-1200}$ 

   =$\text{1700-1200}$ 

   $\text{=500}$

   c,100:{250:[450-4.125-4.25)]}

   =$\text{ 100 : {250:[450 – ( 500 – 100)]} }$  

   $\text{=100:(250 : (450-400)}$

   $\text{=100:(250:50)}$

   $\text{=100 :50}$

   $\text{=2}$

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2. Đáp án:

   `a)2910.`

   `b)500.`

   `c)20.`

   Giải thích các bước giải:

   `a)15.141+53.15.`

   `=15.(141+53).`

   `=15.194.`

   `=2910.`

   `b)17.85+15.17-1200.`

   `=17.(85+15)-1200.`

   `=17.100-1200.`

   `=1700-1200.`

   `=500.`

   `c)100÷[250÷(450-4.125-4.25)].`

   `=100÷{250÷[450-4.(125-25)]}.`

   `=100÷[250÷(450-4.100)].`

   `=100÷[250÷(450-400)].`

   `=100÷(250÷50).`

   `=100÷5.`

   `=20.`

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