bài 1a)x-2/5=1-x/6 b)22/5+1/2.x^2=4.8/5 c)7/2-|x-1/3|=5/2

bài 1a)x-2/5=1-x/6
b)22/5+1/2.x^2=4.8/5
c)7/2-|x-1/3|=5/2

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  1. Đáp án-Giải thích các bước giải:

    Bài 1:

    a)`x-2/5=1-x/6`

    `<=>x+x/6=1+2/5`

    `<=>7/6x=7/5`

    `<=>x=7/5:7/6`

    `<=>x=7/5 . 6/7`

    `<=>x=6/5`

    Vậy `x=6/5`

    b)`22/5+1/2.x^2=4.8/5`

    `<=>22/5 + 1/2.x^2=32/5`

    `<=>1/2 . x^2=32/5-22/5`

    `<=>1/2 .x^2=2`

    `<=>x^2=2:1/2`

    `<=>x^2=4`

    `<=>x=+-2`

    Vậy `x=+-2`

    c)`7/2-|x-1/3|=5/2`

    `<=>|x-1/3|=7/2-5/2`

    `<=>|x-1/3|=1`

    +) `x-1/3=1`

    `<=>x=1+1/3`

    `<=>x=4/3`

    +)`x-1/3=-1`

    `<=>x=-1+1/3`

    `<=>x=-2/3`

    Vậy `x=4/3;x=-2/3.`

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  2. a) `x-2/5 =1-x/6`

    `x+x/6=1+2/5`

    `x.(1+1/6)=7/5`

    `x . 7/6 =7/5`

    `x=7/5 : 7/6`

    `x=6/5`

    b) `22/5 +1/2 .x^2=4. 8/5`

    `22/5 + 1/2 .x^2=32/5`

    `1/2 .x^2=32/5-22/5`

    `1/2 .x^2= 2`

    `x^2 = 2: 1/2`

    `x^2=4`

    `x=2^2=(-2)^2`

    c) `7/2 -|x-1/3|=5/2`

    `|x-1/3|=7/2-5/2`

    `|x-1/3|=1`

    \(\left[ \begin{array}{l}x-\dfrac{1}{3}=1\\x-\dfrac{1}{3}=-1\end{array} \right.\) 

    \(\left[ \begin{array}{l}x=1+\dfrac{1}{3}\\x=-1+\dfrac{1}{3}\end{array} \right.\) 

    \(\left[ \begin{array}{l}x=\dfrac{4}{3}\\x=\dfrac{-2}{3}\end{array} \right.\) 

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