bài 2 tìm x biết1/ 78.[x-64]=2 , 2/[134-x] :36=3 ,3/134[x-3]=35+160 :5 20/07/2021 Bởi Mary bài 2 tìm x biết1/ 78.[x-64]=2 , 2/[134-x] :36=3 ,3/134[x-3]=35+160 :5
Đáp án: $1) x=\dfrac{2497}{39}\\2)x=26\\3)x=\dfrac{7}{2}$ Giải thích các bước giải: $1) 78.(x-64)=2\\\Leftrightarrow x-64=\dfrac{2}{78}=\dfrac{1}{39}\\\Leftrightarrow x=64+\dfrac{1}{39}\\\Leftrightarrow x=\dfrac{2496}{39}+\dfrac{1}{39}\\\Leftrightarrow x=\dfrac{2497}{39}\\2)(134-x):36=3\\\Leftrightarrow 134-x=3.36=108\\\Leftrightarrow x=134-108=26\\3)134.(x-3)=35+160:5\\\Leftrightarrow 134x-402=35+32=67\\\Leftrightarrow 134x=67+402=469\\\Leftrightarrow x=\dfrac{469}{134}=\dfrac{7}{2}$ Bình luận
Đáp án:
$1) x=\dfrac{2497}{39}\\
2)
x=26\\
3)
x=\dfrac{7}{2}$
Giải thích các bước giải:
$1) 78.(x-64)=2\\
\Leftrightarrow x-64=\dfrac{2}{78}=\dfrac{1}{39}\\
\Leftrightarrow x=64+\dfrac{1}{39}\\
\Leftrightarrow x=\dfrac{2496}{39}+\dfrac{1}{39}\\
\Leftrightarrow x=\dfrac{2497}{39}\\
2)
(134-x):36=3\\
\Leftrightarrow 134-x=3.36=108\\
\Leftrightarrow x=134-108=26\\
3)
134.(x-3)=35+160:5\\
\Leftrightarrow 134x-402=35+32=67\\
\Leftrightarrow 134x=67+402=469\\
\Leftrightarrow x=\dfrac{469}{134}=\dfrac{7}{2}$