Bài 2:Tìm x: c.|x-55%|=7/15 d.|3x-1|+2/3=1 18/11/2021 Bởi Claire Bài 2:Tìm x: c.|x-55%|=7/15 d.|3x-1|+2/3=1
Đáp án: Giải thích các bước giải: c) | x-55% | = $\dfrac{7}{15}$ | x – $\dfrac{11}{20}$ | = $\dfrac{7}{15}$ x – $\dfrac{11}{20}$ = ± $\dfrac{7}{15}$ \(\left[ \begin{array}{l}x-\dfrac{11}{20}=\dfrac{7}{5}\\x-\dfrac{11}{20}=\dfrac{-7}{5}\end{array} \right.\) \(\left[ \begin{array}{l}x=\dfrac{7}{5}+\dfrac{11}{20}\\x=\dfrac{-7}{5}+\dfrac{11}{20}\end{array}\right.\) \(\left[ \begin{array}{l}x=\dfrac{39}{20}\\x=\dfrac{-17}{20}\end{array} \right.\) Bình luận
Đáp án: Giải thích các bước giải: `c.|x-55%|=7/15` `=>|x-11/20|=7/15` $=>\left[ \begin{array}{l}x-11/20=7/15\\x-11/20=-7/15\end{array} \right.$ $=>\left[ \begin{array}{l}x=61/60\\x=1/12\end{array} \right.$ `d.|3x-1|+2/3=1` `=>|3x-1|=1/3` $=>\left[ \begin{array}{l}3x-1=1/3\\3x-1=-1/3\end{array} \right.$ $=>\left[ \begin{array}{l}x=4/9\\x=2/9\end{array} \right.$ Bình luận
Đáp án:
Giải thích các bước giải:
c)
| x-55% | = $\dfrac{7}{15}$
| x – $\dfrac{11}{20}$ | = $\dfrac{7}{15}$
x – $\dfrac{11}{20}$ = ± $\dfrac{7}{15}$
\(\left[ \begin{array}{l}x-\dfrac{11}{20}=\dfrac{7}{5}\\x-\dfrac{11}{20}=\dfrac{-7}{5}\end{array} \right.\)
\(\left[ \begin{array}{l}x=\dfrac{7}{5}+\dfrac{11}{20}\\x=\dfrac{-7}{5}+\dfrac{11}{20}\end{array}\right.\)
\(\left[ \begin{array}{l}x=\dfrac{39}{20}\\x=\dfrac{-17}{20}\end{array} \right.\)
Đáp án:
Giải thích các bước giải:
`c.|x-55%|=7/15`
`=>|x-11/20|=7/15`
$=>\left[ \begin{array}{l}x-11/20=7/15\\x-11/20=-7/15\end{array} \right.$
$=>\left[ \begin{array}{l}x=61/60\\x=1/12\end{array} \right.$
`d.|3x-1|+2/3=1`
`=>|3x-1|=1/3`
$=>\left[ \begin{array}{l}3x-1=1/3\\3x-1=-1/3\end{array} \right.$
$=>\left[ \begin{array}{l}x=4/9\\x=2/9\end{array} \right.$