Bài 3 Tính nhanh
A= ( 3 – 1/4 + 2/3 ) – (5 + 1/3 – 6/5 ) – ( 6 – 7/4 + 3/2 )
Bài 3 Tính nhanh A= ( 3 – 1/4 + 2/3 ) – (5 + 1/3 – 6/5 ) – ( 6 – 7/4 + 3/2 )
By Josie
By Josie
Bài 3 Tính nhanh
A= ( 3 – 1/4 + 2/3 ) – (5 + 1/3 – 6/5 ) – ( 6 – 7/4 + 3/2 )
A= ( 3 – 1/4 + 2/3 ) – (5 + 1/3 – 6/5 ) – ( 6 – 7/4 + 3/2 )
=3-1/4+2/3-5-1/3+6/5-6+7/4+3/2
=(3-5-6)+[(-1/4)+7/4-3/2+6/5)+(2/3-1/3]
=-8+6/5+1/3
=-97/65
Chúc học tốt!!
Đáp án:$\frac{-97}{15}$
Giải thích các bước giải:
A= ( 3 – 1/4 + 2/3 ) – (5 + 1/3 – 6/5 ) – ( 6 – 7/4 + 3/2 )
= 3 – $\frac{1}{4}$ + $\frac{2}{3}$ – 5 -$\frac{1}{3}$ + $\frac{6}{5}$ -6 + $\frac{7}{4}$ – $\frac{3}{2}$
= (3-5-6) + ( $\frac{-1}{4}$ + $\frac{7}{4}$ ) + ( $\frac{2}{3}$ – $\frac{1}{3}$ ) + $\frac{6}{5}$ + $\frac{-3}{2}$
= -8 + $\frac{3}{2}$ + $\frac{1}{3}$ + $\frac{6}{5}$ + $\frac{-3}{2}$
= -8 + ( $\frac{3}{2}$ + $\frac{-3}{2}$ ) + $\frac{6}{5}$ + $\frac{1}{3}$
= -8 + $\frac{6}{5}$ + $\frac{1}{3}$
=$\frac{-34}{5}$ + $\frac{1}{3}$
=$\frac{-97}{15}$
@Nguyenbatdiet
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