bài đội tuyển trường mình giải hộ mình 2 ý x ²+3x-10=0 x.(x-1)=12 05/11/2021 Bởi aikhanh bài đội tuyển trường mình giải hộ mình 2 ý x ²+3x-10=0 x.(x-1)=12
`x ²+3x-10=0 ` `(x ²-2x)+(5x-10)=0 ` `x(x-2)+5(x-2)=0 ` `(x-2)(x+5)=0 ` \(\left[ \begin{array}{l}x-2=0\\x+5=0\end{array} \right.\) \(\left[ \begin{array}{l}x=2\\x=-5\end{array} \right.\) `x(x-1)=12` `x^2-x-12=0` `(x^2-4x)+(3x-12)=0` `x(x-4)+3(x-4)=0` `(x-4)(x+3)=0` \(\left[ \begin{array}{l}x-4=0\\x+3=0\end{array} \right.\) \(\left[ \begin{array}{l}x=4\\x=-3\end{array} \right.\) Bình luận
`x ²+3x-10=0 `
`(x ²-2x)+(5x-10)=0 `
`x(x-2)+5(x-2)=0 `
`(x-2)(x+5)=0 `
\(\left[ \begin{array}{l}x-2=0\\x+5=0\end{array} \right.\)
\(\left[ \begin{array}{l}x=2\\x=-5\end{array} \right.\)
`x(x-1)=12`
`x^2-x-12=0`
`(x^2-4x)+(3x-12)=0`
`x(x-4)+3(x-4)=0`
`(x-4)(x+3)=0`
\(\left[ \begin{array}{l}x-4=0\\x+3=0\end{array} \right.\)
\(\left[ \begin{array}{l}x=4\\x=-3\end{array} \right.\)