bài : phân tích đa thức thành nhân tử a,x mũ 2+8x+16 b,(2x-1)mũ 3 + 8 c,8x mũ 3-12x mũ 2+6x-2 d,8x mũ 3-12x mũ 2+6x-1 28/10/2021 Bởi Elliana bài : phân tích đa thức thành nhân tử a,x mũ 2+8x+16 b,(2x-1)mũ 3 + 8 c,8x mũ 3-12x mũ 2+6x-2 d,8x mũ 3-12x mũ 2+6x-1
`a)x^2+8x+16` `=x^2+2.x.4+4^2` `=(x+4)^2` `b)(2x-1)^3+8` `=(2x-1)^3+2^3` `=(2x-1+2)[(2x-1)^2+2(2x-1)+2^2]` `=(2x+1)(4x^2-4x+1+4x-2+4)` `=(2x+1)(4x^2+3)` `c)8x^3-12x^2+6x-2` `=8x^3-8x^2-4x^2+4x+2x-2` `=8x^2(x-1)-4x(x-1)+2(x-1)` `=(x-1)(8x^2-4x+2)` `d)8x^3-12x^2+6x-1` `=(2x)^3-3.(2x)^2.1+3.2x.1-1^3` `=(2x-1)^3` Bình luận
`a,x^2+8x+16` `=(x+4)^2` `b,(2x-1)^3 + 8` `=8x^3-12x^2+6x+7` `=(2x+1)(4x^2-8x+7)` `c,8x^3-12x^2+6x-2` `=2(4x^3-6x^2+3x-1)` `=2(x-1)(4x^2-2x+1)` `d,8x^3-12x^2+6x-1` `=(2x-1)^3` Bình luận
`a)x^2+8x+16`
`=x^2+2.x.4+4^2`
`=(x+4)^2`
`b)(2x-1)^3+8`
`=(2x-1)^3+2^3`
`=(2x-1+2)[(2x-1)^2+2(2x-1)+2^2]`
`=(2x+1)(4x^2-4x+1+4x-2+4)`
`=(2x+1)(4x^2+3)`
`c)8x^3-12x^2+6x-2`
`=8x^3-8x^2-4x^2+4x+2x-2`
`=8x^2(x-1)-4x(x-1)+2(x-1)`
`=(x-1)(8x^2-4x+2)`
`d)8x^3-12x^2+6x-1`
`=(2x)^3-3.(2x)^2.1+3.2x.1-1^3`
`=(2x-1)^3`
`a,x^2+8x+16`
`=(x+4)^2`
`b,(2x-1)^3 + 8`
`=8x^3-12x^2+6x+7`
`=(2x+1)(4x^2-8x+7)`
`c,8x^3-12x^2+6x-2`
`=2(4x^3-6x^2+3x-1)`
`=2(x-1)(4x^2-2x+1)`
`d,8x^3-12x^2+6x-1`
`=(2x-1)^3`