Bai2.Cho 2 bieu thuc
A=canx+2/canx-5 va B=3/canx+5 + 20-2canx/x-25
a,tinh gia tri bieu thu a khi x =16
b,cmB=1/canx-5
Bai2.Cho 2 bieu thuc
A=canx+2/canx-5 va B=3/canx+5 + 20-2canx/x-25
a,tinh gia tri bieu thu a khi x =16
b,cmB=1/canx-5
Đáp án:
B2:
a. A=-6
Giải thích các bước giải:
\(\begin{array}{l}
B2:\\
a.A = \dfrac{{\sqrt x + 2}}{{\sqrt x – 5}}\\
Thay:x = 16\\
\to A = \dfrac{{\sqrt {16} + 2}}{{\sqrt {16} – 5}} = \dfrac{{4 + 2}}{{4 – 5}} = – 6\\
b.B = \dfrac{3}{{\sqrt x + 5}} + \dfrac{{20 – 2\sqrt x }}{{x – 5}}\\
= \dfrac{{3\left( {\sqrt x – 5} \right) + 20 – 2\sqrt x }}{{\left( {\sqrt x + 5} \right)\left( {\sqrt x – 5} \right)}}\\
= \dfrac{{3\sqrt x – 15 + 20 – 2\sqrt x }}{{\left( {\sqrt x + 5} \right)\left( {\sqrt x – 5} \right)}}\\
= \dfrac{{\sqrt x + 5}}{{\left( {\sqrt x + 5} \right)\left( {\sqrt x – 5} \right)}}\\
= \dfrac{1}{{\sqrt x – 5}}
\end{array}\)