baif1: 2 ³.6-[2 ³ .3+5(32:16) ² ]
125-(x-5):3=45
2 ² . 5 -|x|:3 ²=2 ³ +(-18)
baif1: 2 ³.6-[2 ³ .3+5(32:16) ² ] 125-(x-5):3=45 2 ² . 5 -|x|:3 ²=2 ³ +(-18)
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baif1: 2 ³.6-[2 ³ .3+5(32:16) ² ]
125-(x-5):3=45
2 ² . 5 -|x|:3 ²=2 ³ +(-18)
Giải thích các bước giải:
` 2 ³.6-[2 ³ .3+5(32:16) ² ]`
`=8.6-[8.3+5.2^2]`
`=48-[24+5.4]`
`=48-[24+20]`
`=48-44`
`=4`
`125-(x-5):3=45`
`=>(x-5):3=125-45`
`=>(x-5):3=80`
`=>x-5=80\times3`
`=>x-5=240`
`=>x=240+5`
`=>x=245`
`2 ² . 5 -|x|:3 ²=2 ³ +(-18)`
`=>4 .5-|x|:9=8+(-18)`
`=>20-|x|:9=-10`
`=>|x|:9=20+10`
`=>|x|:9=30`
`=>|x|=30\times9`
`=>|x|=270`
`=>`\(\left[ \begin{array}{l}x=270\\x=-270\end{array} \right.\)
Đáp án:
`2 ³.6-[2 ³ .3+5(32:16) ² ]`
`= 8 . 6 – [8 . 3 + 5 . 2^2]`
`= 48 – [24 + 5 . 4]`
`= 48 – [24 + 20]`
`= 48 – 44`
`= 4`
`125 – (x-5) : 3 = 45`
`(x – 5) : 3 = 125 – 45`
`(x – 5) : 3 = 80`
`x – 5 = 80 × 3`
`x – 5 =240`
`x = 240 + 5`
`x = 245`
Vậy `x = 245`
`2 ² . 5 -|x|:3 ²=2 ³ +(-18)`
`4 . 5 – |x| : 9 = 8 + (-18)`
`20 – |x| : 9 = -10`
`|x| : 9 = 20 + 10`
`|x| : 9 = 30`
`|x| = 30 × 9`
`|x| = 270`
`⇒ x = 270` hoặc `x = -270`
Vậy `x ∈ {270 ; -270}`