biết x+y=0 ,tính giá trị đa thức sau C=2x+2y=3xy ( x+y) +5 ( x^3y^2 +x^2y^3) +2 D=3xy (x+y) + 2x^3y+2x^2 y^2+5

$C=2x+2y+3xy(x+y)+5(x^3y^2+x^2y^3)+2\\=2(x+y)+3xy(x+y)+5x^2y^2(x+y)+2\\=2.0+3xy.0+5x^2y^2.0+2\\=0+0+0+2\\=2\\D=3xy(x+y)+2x^3y+2x^2y^2+5\\=3xy(x+y)+2x^2y(x+y)+5\\=3xy.0+2x^2y.0+5\\=0+0+5\\=5$