C1:42.98-{[(18-2^3):2+3^2]} C2:(56.46-25.23):23 C3 1024:(-2^4)+140:(38+2^5)-7^23:7^21 11/09/2021 Bởi Arya C1:42.98-{[(18-2^3):2+3^2]} C2:(56.46-25.23):23 C3 1024:(-2^4)+140:(38+2^5)-7^23:7^21
$C1$ $42.98 – [(18-2^3) : 2 + 3^2]$ $= 42.98 – [(18-8):2 + 9]$ $= 42. 98 – 14$ $= 14.(3.98-1)$ $= 4102$ $C2. (56.46 – 25.23) : 23$ $= 56.46:23 – 25.23:23$ $= 56.2 – 25$ $= 112 – 25$ $= 87$ $C3.1024:(-2^4)+140:(38+2^5)-7^23:7^21$ $= 1024 : 16 + 140 : 70 – 49$ $= 64 + 2 – 49$ $= 17$ Bình luận
1. 42.98−[(18−23):2+32]42.98−[(18−23):2+32] =42.98−[(18−8):2+9]=42.98−[(18−8):2+9] =42.98−14=42.98−14 =14.(3.98−1)=14.(3.98−1) =4102=4102 2 .(56.46−25.23):23C2.(56.46−25.23):23 =56.46:23−25.23:23=56.46:23−25.23:23 =56.2−25=56.2−25 =112−25=112−25 =87=87 3 .1024:(-2^4)+140:(38+2^5)-7^23:7^21$ =1024:16+140:70−49=1024:16+140:70−49 =64+2−49=64+2−49 =17 Chúc bạn hok tập tốt ạ Bình luận
$C1$ $42.98 – [(18-2^3) : 2 + 3^2]$
$= 42.98 – [(18-8):2 + 9]$
$= 42. 98 – 14$
$= 14.(3.98-1)$
$= 4102$
$C2. (56.46 – 25.23) : 23$
$= 56.46:23 – 25.23:23$
$= 56.2 – 25$
$= 112 – 25$
$= 87$
$C3.1024:(-2^4)+140:(38+2^5)-7^23:7^21$
$= 1024 : 16 + 140 : 70 – 49$
$= 64 + 2 – 49$
$= 17$
1. 42.98−[(18−23):2+32]42.98−[(18−23):2+32]
=42.98−[(18−8):2+9]=42.98−[(18−8):2+9]
=42.98−14=42.98−14
=14.(3.98−1)=14.(3.98−1)
=4102=4102
2 .(56.46−25.23):23C2.(56.46−25.23):23
=56.46:23−25.23:23=56.46:23−25.23:23
=56.2−25=56.2−25
=112−25=112−25
=87=87
3 .1024:(-2^4)+140:(38+2^5)-7^23:7^21$
=1024:16+140:70−49=1024:16+140:70−49
=64+2−49=64+2−49
=17
Chúc bạn hok tập tốt ạ