C2H5OH–> CH3COOH–> CH3COONa–> CH3COOH–> CH3COOC2H5 Hoàn thành Chuỗi pứ 21/07/2021 Bởi Eliza C2H5OH–> CH3COOH–> CH3COONa–> CH3COOH–> CH3COOC2H5 Hoàn thành Chuỗi pứ
$ C_2H_5OH + O_2 \xrightarrow{\text{Men giấm}} CH_3COOH + H_2O $ $ CH_3COOH + Na \rightarrow CH_3COONa + \dfrac{1}{2}H_2 ↑ $ $ CH_3COONa + H_2O \rightarrow CH_3COOH + NaOH $ $ CH_3COOH + C_2H_5OH ⇄ CH_3COOC_2H_5 + H_2O $ (Điều kiện : $H_2SO_4đ,t^o$) Bình luận
$C_2H_5OH+O_2\xrightarrow{\text{Men giấm}}CH_3COOH+H_2O$ `2CH_3COOH+Na_2CO_3->2CH_3COONa+CO_2+H_2O` `CH_3COONa+HCl->CH_3COOH+NaCl` $CH_3COOH+C_2H_5OH\leftarrow\xrightarrow[H^+]{t^o}CH_3COOC_2H_5+H_2O$ Bình luận
$ C_2H_5OH + O_2 \xrightarrow{\text{Men giấm}} CH_3COOH + H_2O $
$ CH_3COOH + Na \rightarrow CH_3COONa + \dfrac{1}{2}H_2 ↑ $
$ CH_3COONa + H_2O \rightarrow CH_3COOH + NaOH $
$ CH_3COOH + C_2H_5OH ⇄ CH_3COOC_2H_5 + H_2O $
(Điều kiện : $H_2SO_4đ,t^o$)
$C_2H_5OH+O_2\xrightarrow{\text{Men giấm}}CH_3COOH+H_2O$
`2CH_3COOH+Na_2CO_3->2CH_3COONa+CO_2+H_2O`
`CH_3COONa+HCl->CH_3COOH+NaCl`
$CH_3COOH+C_2H_5OH\leftarrow\xrightarrow[H^+]{t^o}CH_3COOC_2H_5+H_2O$