cach tinh bai : {A E N|x E 5q + 4 | x < 131 } 23/09/2021 Bởi Isabelle cach tinh bai : {A E N|x E 5q + 4 | x < 131 }
Do $x\in\mathbb N$ và $x<131$ $\Rightarrow 0\le x<131$ $\Rightarrow 0\le5q+4<131$ $\Rightarrow -4\le5q<131-4$ $\Rightarrow -4\le5q<127$ $\Rightarrow \dfrac{-4}{5}\le q<\dfrac{127}{5}$ $\Rightarrow q \in \{\dfrac{-4}{5};\dfrac{-3}{5};\dfrac{-2}{5};\dfrac{-1}{5};0;\dfrac{1}{5};\dfrac{2}{5};\dfrac{3}{5};\dfrac{4}{5};…\dfrac{126}{5}\}$ $\Rightarrow x \in \{0;1;2;3;4;5;6;7;8;…130\}$. $\Rightarrow A=\{0;1;2;3;4;5;…130\}$ Bình luận
Do $x\in\mathbb N$ và $x<131$
$\Rightarrow 0\le x<131$
$\Rightarrow 0\le5q+4<131$
$\Rightarrow -4\le5q<131-4$
$\Rightarrow -4\le5q<127$
$\Rightarrow \dfrac{-4}{5}\le q<\dfrac{127}{5}$
$\Rightarrow q \in \{\dfrac{-4}{5};\dfrac{-3}{5};\dfrac{-2}{5};\dfrac{-1}{5};0;\dfrac{1}{5};\dfrac{2}{5};\dfrac{3}{5};\dfrac{4}{5};…\dfrac{126}{5}\}$
$\Rightarrow x \in \{0;1;2;3;4;5;6;7;8;…130\}$.
$\Rightarrow A=\{0;1;2;3;4;5;…130\}$