Căn X^2-1 – căn 3x^2+4x+1 = (8-2x).căn x+1

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1. `\sqrt(x^2-1)-\sqrt(3x^2+4x+1)=(8-2x)\sqrt(x+1)`

   `⇔\sqrt((x-1)(x+1))-3\sqrt((x+1/3)(x+1))-(8-2x)\sqrt(x+1)=0`

   `⇔\sqrt(x+1)(\sqrt(x-1)-3\sqrt(x+1/3)-8+2x)=0`

   ⇔\(\left[ \begin{array}{l}\sqrt(x+1)=0\\\sqrt(x-1)-3\sqrt(x+1/3)-8+2x=0\end{array} \right.\) 

   ⇔\(\left[ \begin{array}{l}x+1=0\\(x-5)(1/\sqrt((x-1)+2)+2-1/(\sqrt((x+1/3)+4)=0\end{array} \right.\) 

   ⇔\(\left[ \begin{array}{l}x=-1\\x-5=0(1/\sqrt((x-1)+2)+2-1/(\sqrt((x+1/3)+4>0)\end{array} \right.\) 

   ⇔\(\left[ \begin{array}{l}x=-1\\x=5\end{array} \right.\) 

    

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