Toán căn bậc hai(3-2căn bậc hai(2)) căn bậc hai(7-4căn bậc hai(3)) 10/07/2021 By Samantha căn bậc hai(3-2căn bậc hai(2)) căn bậc hai(7-4căn bậc hai(3))
`\sqrt{3-2\sqrt{2}}` `= \sqrt{2-2\sqrt{2}+1}` `= \sqrt{(\sqrt{1})^2(\sqrt{2})^2-2\sqrt{2}+(\sqrt{1})^2}` `= \sqrt{(1.\sqrt{2}-1)^2}` `= 1 . \sqrt{2} – 1` `= \sqrt{2} – 1` `\sqrt{7-4\sqrt{3}}` `=\sqrt{3-4\sqrt{3}+4}` `=\sqrt{(\sqrt{1})^2(\sqrt{3})^2-4\sqrt{3}+(\sqrt{4})^2}` `=\sqrt{(1.\sqrt{3}-2)^2}` `=\sqrt{(2-1.\sqrt{3})^2}` `= 2 – 1.\sqrt{3}` `= 2 – \sqrt{3}` Trả lời
`\sqrt{3-2\sqrt{2}}`
`= \sqrt{2-2\sqrt{2}+1}`
`= \sqrt{(\sqrt{1})^2(\sqrt{2})^2-2\sqrt{2}+(\sqrt{1})^2}`
`= \sqrt{(1.\sqrt{2}-1)^2}`
`= 1 . \sqrt{2} – 1`
`= \sqrt{2} – 1`
`\sqrt{7-4\sqrt{3}}`
`=\sqrt{3-4\sqrt{3}+4}`
`=\sqrt{(\sqrt{1})^2(\sqrt{3})^2-4\sqrt{3}+(\sqrt{4})^2}`
`=\sqrt{(1.\sqrt{3}-2)^2}`
`=\sqrt{(2-1.\sqrt{3})^2}`
`= 2 – 1.\sqrt{3}`
`= 2 – \sqrt{3}`
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