Cân bằng phương trình oxi hóa khử 1. FeO + H2SO4 —-> Fe2(SO4)3 + SO2 + H2O 2. Fe3O4 + H2SO4 ——> Fe2(SO4)3 + SO2 + H2O

Giải thích các bước giải:

\[\begin{array}{l} 1.\\ \mathop {Fe}\limits^{ + 2} O + {H_2}\mathop S\limits^{ + 6} {O_4} \to {\mathop {Fe}\limits^{ + 3} _2}{(S{O_4})_3} + \mathop S\limits^{ + 4} {O_2} + {H_2}O\\ \mathop {2Fe}\limits^{ + 2} \to {\mathop {Fe}\limits^{ + 3} _2} + 2e\quad |\; \times 1\\ \mathop S\limits^{ + 6} + 2e \to \mathop S\limits^{ + 4} \quad \quad {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} | \times 1\\ \Rightarrow 2FeO + 4{H_2}S{O_4} \to F{e_2}{(S{O_4})_3} + S{O_2} + 4{H_2}O\\ 2.\\ {\mathop {Fe}\limits^{ + \frac{8}{3}} _3}{O_4} + {H_2}\mathop S\limits^{ + 6} {O_4} \to {\mathop {Fe}\limits^{ + 3} _2}{(S{O_4})_3} + \mathop S\limits^{ + 4} {O_2} + {H_2}O\\ 2{\mathop {Fe}\limits^{ + \frac{8}{3}} _3} \to {\mathop {3Fe}\limits^{ + 3} _2} + 2e\quad |\; \times 1\qquad \\ \mathop S\limits^{ + 6} + 2e \to \mathop S\limits^{ + 4} \quad \quad \quad {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} |\; \times 1\\ \Rightarrow 2F{e_3}{O_4} + 10{H_2}S{O_4} \to 3F{e_2}{(S{O_4})_3} + S{O_2} + 10{H_2}O \end{array}\]